### Short Answer

### 2.1 Relative Motion, Distance, and Displacement

While standing on a sidewalk facing the road, you see a bicyclist passing by toward your right. In the reference frame of the bicyclist, in which direction are you moving?

- in the same direction of motion as the bicyclist
- in the direction opposite the motion of the bicyclist
- stationary with respect to the bicyclist
- in the direction of velocity of the bicyclist

- Displacement of the ball is twice the length of the lane, while the distance is zero.
- Displacement of the ball is zero, while the distance is twice the length of the lane.
- Both the displacement and distance for the ball are equal to zero.
- Both the displacement and distance for the ball are twice the length of the lane.

- The distance is $63\mathrm{\xcf\u20ac}\phantom{\rule{thinmathspace}{0ex}}\text{cm}$ with a displacement of zero.
- The distance is $7\phantom{\rule{thinmathspace}{0ex}}\text{cm}$ with a displacement of zero.
- The distance is $63\mathrm{\xcf\u20ac}\phantom{\rule{thinmathspace}{0ex}}\text{cm}$ with a displacement of $14\phantom{\rule{thinmathspace}{0ex}}\text{cm}$.
- The distance is $7\phantom{\rule{thinmathspace}{0ex}}\text{cm}$ with a displacement of $63\mathrm{\xcf\u20ac}\phantom{\rule{thinmathspace}{0ex}}\text{cm}$.

### 2.2 Speed and Velocity

- t/6
- t/3
- 3t
- 6t

What can you infer from the statement, *Velocity of an object is zero*?

- Object is in linear motion with constant velocity.
- Object is moving at a constant speed.
- Object is either at rest or it returns to the initial point.
- Object is moving in a straight line without changing its direction.

- Reduce the distance that the object travels by half, keeping the time constant, or keep the distance constant and double the time.
- Double the distance that the object travels, keeping the time constant, or keep the distance constant and reduce the time by half.
- Reduce the distance that the object travels to one-fourth, keeping the time constant, or keep the distance constant and increase the time by fourfold.
- Increase the distance by fourfold, keeping the time constant, or keep the distance constant and reduce the time by one-fourth.

- His average velocity is zero because his total distance is zero.
- His average velocity is zero because his total displacement is zero.
- His average velocity is zero because the number of laps completed is an odd number.
- His average velocity is zero because the velocity of each successive lap is equal and opposite.

### 2.3 Position vs. Time Graphs

A hockey puck is shot down the arena in a straight line. Assume it does not slow until it is stopped by an opposing player who sends it back in the direction it came. The players are 20 m apart and it takes 1 s for the puck to go there and back. Which of the following describes the graph of the displacement over time? Consider the initial direction of the puck to be positive.

- The graph is an upward opening V.
- The graph is a downward opening V.
- The graph is an upward opening U.
- The graph is downward opening U.

A defensive player kicks a soccer ball 20 m back to her own goalie. It stops just as it reaches her. She sends it back to the player. Without knowing the time it takes, draw a rough sketch of the displacement over time. Does this graph look similar to the graph of the hockey puck from the previous question?

- Yes, the graph is similar to the graph of the hockey puck.
- No, the graph is not similar to the graph of the hockey puck.
- The graphs cannot be compared without knowing the time the soccer ball was rolling.

What are the net displacement, total distance traveled, and total average velocity in the previous two problems?

- net displacement = 0 m, total distance = 20 m, total average velocity = 20 m/s
- net displacement = 0 m, total distance = 40 m, total average velocity = 20 m/s
- net displacement = 0 m, total distance = 20 m, total average velocity = 0 m/s
- net displacement = 0 m, total distance = 40 m, total average velocity = 0 m/s

- The graph would take the shape of a v with the point down.
- The graph would take the shape of a v with the point up.
- The graph would take the shape of a parabola with the legs pointing up.
- The graph would take the shape of a parabola with the legs pointing down.

### 2.4 Velocity vs. Time Graphs

What would the velocity vs. time graph of the object whose position is shown in the graph look like?

- It is a straight line with negative slope.
- It is a straight line with positive slope.
- It is a horizontal line at some negative value.
- It is a horizontal line at some positive value.

Which statement correctly describes the objectâ€™s speed, as well as what a graph of acceleration vs. time would look like?

- The object is not speeding up, and the acceleration vs. time graph is a horizontal line at some negative value.
- The object is not speeding up, and the acceleration vs. time graph is a horizontal line at some positive value.
- The object is speeding up, and the acceleration vs. time graph is a horizontal line at some negative value.
- The object is speeding up, and the acceleration vs. time graph is a horizontal line at some positive value.

Calculate that objectâ€™s net displacement over the time shown.

- 540 m
- 2,520 m
- 2,790 m
- 5,040 m

What is the objectâ€™s average velocity?

- 18 m/s
- 84 m/s
- 93 m/s
- 168 m/s