Problems
5.1 Vector Addition and Subtraction: Graphical Methods
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The resultant velocity of the boat will be 10.0\,\text{m/s}. The boat will go toward his right at an angle of 26.6^\circ\! to a line drawn across the river.
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The resultant velocity of the boat will be 10.0\,\text{m/s}. The boat will go toward his left at an angle of 26.6^\circ\! to a line drawn across the river.
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The resultant velocity of the boat will be 15.8\,\text{m/s}. The boat will go toward his right at an angle of 18.4^\circ\! to a line drawn across the river.
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The resultant velocity of the boat will be 15.8\,\text{m/s}. The boat will go toward his left at an angle of 18.4^\circ\! to a line drawn across the river.
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It should head in a direction 22.6^\circ\! east of south.
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It should head in a direction 22.6^\circ\! south of east.
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It should head in a direction 45.0^\circ\! east of south.
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It should head in a direction 45.0^\circ south of east.
5.2 Vector Addition and Subtraction: Analytical Methods
A person walks 10.0 m north and then 2.00 m east. Solving analytically, what is the resultant displacement of the person?
- = 10.2 m, θ = 78.7º east of north
- = 10.2 m, θ = 78.7º north of east
- = 12.0 m, θ = 78.7º east of north
- = 12.0 m, θ = 78.7º north of east
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10.84\,\text{m}
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65.1\,\text{m}
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66.04\,\text{m}
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80.00\,\text{m}
5.3 Projectile Motion
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2.35\,\text{m}
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3.01\,\text{m}
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70.35\,\text{m}
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90.44\,\text{m}
A person wants to fire a water balloon cannon such that it hits a target 100 m away. If the cannon can only be launched at 45° above the horizontal, what should be the initial speed at which it is launched?
- 31.3 m/s
- 37.2 m/s
- 980.0 m/s
- 1,385.9 m/s
5.4 Inclined Planes
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\mu_\text{k} = 0
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\mu_\text{k} = 0.18
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\mu_\text{k} = 5.88
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\mu_\text{k} = \infty
A skier with a mass of 55 kg is skiing down a snowy slope that has an incline of 30°. Find the coefficient of kinetic friction for the skier if friction is known to be 25 N .
5.5 Simple Harmonic Motion
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0.08\,\text{s}
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0.49\,\text{s}
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4.9\,\text{s}
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80\,\text{s}
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0.125\,\text{N/m}
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0.202\,\text{N/m}
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0.81\,\text{N/m}
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4.93\,\text{N/m}