### Problems

#### 5.1 Vector Addition and Subtraction: Graphical Methods

- The resultant velocity of the boat will be 10.0\,\text{m/s}. The boat will go toward his right at an angle of 26.6^\circ\! to a line drawn across the river.
- The resultant velocity of the boat will be 10.0\,\text{m/s}. The boat will go toward his left at an angle of 26.6^\circ\! to a line drawn across the river.
- The resultant velocity of the boat will be 15.8\,\text{m/s}. The boat will go toward his right at an angle of 18.4^\circ\! to a line drawn across the river.
- The resultant velocity of the boat will be 15.8\,\text{m/s}. The boat will go toward his left at an angle of 18.4^\circ\! to a line drawn across the river.

- It should head in a direction 22.6^\circ\! east of south.
- It should head in a direction 22.6^\circ\! south of east.
- It should head in a direction 45.0^\circ\! east of south.
- It should head in a direction 45.0^\circ south of east.

#### 5.2 Vector Addition and Subtraction: Analytical Methods

A person walks 10.0 m north and then 2.00 m east. Solving analytically, what is the resultant displacement of the person?

- $\stackrel{\xe2\u2020\u2019}{\text{R}}$ = 10.2 m, Î¸ = 78.7Âº east of north
- $\stackrel{\xe2\u2020\u2019}{\text{R}}$ = 10.2 m, Î¸ = 78.7Âº north of east
- $\stackrel{\xe2\u2020\u2019}{\text{R}}$ = 12.0 m, Î¸ = 78.7Âº east of north
- $\stackrel{\xe2\u2020\u2019}{\text{R}}$ = 12.0 m, Î¸ = 78.7Âº north of east

- 10.84\,\text{m}
- 65.1\,\text{m}
- 66.04\,\text{m}
- 80.00\,\text{m}

#### 5.3 Projectile Motion

- 2.35\,\text{m}
- 3.01\,\text{m}
- 70.35\,\text{m}
- 90.44\,\text{m}

A person wants to fire a water balloon cannon such that it hits a target 100 m away. If the cannon can only be launched at 45Â° above the horizontal, what should be the initial speed at which it is launched?

- 31.3 m/s
- 37.2 m/s
- 980.0 m/s
- 1,385.9 m/s

#### 5.4 Inclined Planes

- \mu_\text{k} = 0
- \mu_\text{k} = 0.18
- \mu_\text{k} = 5.88
- \mu_\text{k} = \infty

A skier with a mass of 55 kg is skiing down a snowy slope that has an incline of 30Â°. Find the coefficient of kinetic friction for the skier if friction is known to be 25 N .

- $\mathrm{\xce\xbc}k=0$
- $\mathrm{\xce\xbc}k=0.05$
- $\mathrm{\xce\xbc}k=0.09$
- $\mathrm{\xce\xbc}k=\mathrm{\xe2\u02c6\u017e}$

#### 5.5 Simple Harmonic Motion

- 0.08\,\text{s}
- 0.49\,\text{s}
- 4.9\,\text{s}
- 80\,\text{s}

- 0.125\,\text{N/m}
- 0.202\,\text{N/m}
- 0.81\,\text{N/m}
- 4.93\,\text{N/m}