Problem
29-1
HOCH2CH(OH)CH2OH + ATP → HOCH2CH(OH)CH2OPO32− + ADP
Problem
29-2
Caprylyl CoA → Hexanoyl CoA → Butyryl CoA → 2 Acetyl CoA
Problem
29-4
The dehydration is an E1cB reaction.
Problem
29-5
At C2, C4, C6, C8, and so forth
Problem
29-6
The Si face
Problem
29-7
Steps 7 and 10
Problem
29-8
Steps 1, 3: Phosphate transfers; steps 2, 5, 8: isomerizations; step 4: retro-aldol reaction; step 5: oxidation and nucleophilic acyl substitution; steps 7, 10: phosphate transfers; step 9: E1cB dehydration
Problem
29-9
C1 and C6 of glucose become –CH3 groups; C3 and C4 become CO2.
Problem
29-10
Citrate and isocitrate
Problem
29-11
E1cB elimination of water, followed by conjugate addition
Problem
29-12
pro-R; anti geometry
Problem
29-13
The reaction occurs by two sequential nucleophilic acyl substitutions, the first by a cysteine residue in the enzyme, with phosphate as leaving group, and the second by hydride donation from NADH, with the cysteine residue as leaving group.
Problem
29-14
Initial imine formation between PMP and α-ketoglutarate is followed by double-bond rearrangement to an isomeric imine and hydrolysis.
Problem
29-15
(CH3)2CHCH2COCO2−
Problem
29-16
Asparagine