Chapter 11

a. 0 N; b. $2.4\times {10}^{\mathrm{-14}}\widehat{k}\text{N};$ c. $2.4\times {10}^{\mathrm{-14}}\widehat{j}\text{N};$ d. $(7.2\widehat{j}+2.2\widehat{k})\times {10}^{\mathrm{-15}}\text{N}$

a. $9.6\times {10}^{\mathrm{-12}}\text{N}$ toward the south; b. $\frac{w}{F_{\text{m}}}=1.7\times {10}^{\mathrm{-15}}$

a. bends upward; b. bends downward

a. aligned or anti-aligned; b. perpendicular

a. 1.1 T; b. 1.6 T

0.32 m

Both are field dependent. Electrical force is dependent on charge, whereas magnetic force is dependent on current or rate of charge flow.

The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. The direction of these forces however are opposite of each other. The accelerations are opposite in direction and the electron has a larger acceleration than the proton due to its smaller mass.

The magnetic field must point parallel or anti-parallel to the velocity.

A compass points toward the north pole of an electromagnet.

Velocity and magnetic field can be set together in any direction. If there is a force, the velocity is perpendicular to it. The magnetic field is also perpendicular to the force if it exists.

A force on a wire is exerted by an external magnetic field created by a wire or another magnet.

Poor conductors have a lower charge carrier density, n, which, based on the Hall effect formula, relates to a higher Hall potential. Good conductors have a higher charge carrier density, thereby a lower Hall potential.

a. left; b. into the page; c. up the page; d. no force; e. right; f. down

a. right; b. into the page; c. down

a. into the page; b. left; c. out of the page

a. $2.64\times {10}^{\mathrm{-8}}\text{N};$ north b. The force is very small, so this implies that the effect of static charges on airplanes is negligible.

$10.1\text{°};169.9\text{°}$

4.27 m

a. $4.80\times {10}^{\mathrm{-19}}\text{C};$ b. 3; c. This ratio must be an integer because charges must be integer numbers of the basic charge of an electron. There are no free charges with values less than this basic charge, and all charges are integer multiples of this basic charge.

(a) 3.27 x 10³ m/s (b) 1252.5 m (c) 29.2 m (d) 0.683 m.

a. $1.8\times {10}^7\text{m/s};$ b. $6.8\times {10}^6\text{eV};$ c. $3.4\times {10}^6\text{V}$

a. left; b. into the page; c. up; d. no force; e. right; f. down

a. into the page; b. left; c. out of the page

a. 2.50 N; b. This means that the light-rail power lines must be attached in order not to be moved by the force caused by Earth’s magnetic field.

a. $\tau =NIAB,$ so $\tau$ decreases by 5.00% if B decreases by 5.00%; b. 5.26% increase

10.0 A

$\text{A}·{\text{m}}^2·\text{T}=\text{A}·{\text{m}}^2.\frac{\text{N}}{\text{A}·\text{m}}=\text{N}·\text{m}$

$3.48\times {10}^{\mathrm{-26}}\text{N}·\text{m}$

$0.666\text{N}·\text{m}$

$5.8\times {10}^{\mathrm{-6}}\text{V}$

$4.8\times {10}^7\text{C/kg}$

a. $4.4\times {10}^{\mathrm{-8}}\text{s};$ b. 0.21 m

a. $1.92\times {10}^{\mathrm{-12}}\text{J};$ b. 12 MeV; c. 12 MV; d. $5.2\times {10}^{\mathrm{-8}}\text{s};$ e. $1.92\times {10}^{\mathrm{-12}}\text{J},$ 12 MeV, 12 V, $10.4\times {10}^{\mathrm{-8}}\text{s}$

a. $2.50\times {10}^{\mathrm{-2}}\text{m};$ b. Yes, this distance between their paths is clearly big enough to separate the U-235 from the U-238, since it is a distance of 2.5 cm.

$\mathrm{-7.2}\times {10}^{\mathrm{-15}}\text{N}\widehat{j}$

$9.8\times {10}^{\mathrm{-5}}\widehat{j}\text{T};$ the magnetic and gravitational forces must balance to maintain dynamic equilibrium

$1.13\times {10}^{\mathrm{-3}}\text{T}$

$(1.6\widehat{i}-1.4\widehat{j}-1.1\widehat{k})\times {10}^5\text{V/m}$

a. circular motion in a north, down plane; b. $(1.61\widehat{j}-0.58\widehat{k})\times {10}^{\mathrm{-14}}\text{N}$

The proton has more mass than the electron; therefore, its radius and period will be larger.

$1.3\times {10}^{\mathrm{-25}}\text{kg}$

1:0.707:1

1/4

a. $2.3\times {10}^{\mathrm{-4}}\text{m};$ b. $1.37\times {10}^{\mathrm{-4}}\text{m}$

a. $30.0\text{°};$ b. 4.80 N

a. 0.283 N; b. 0.4 N; c. 0 N; d. 0 N

0 N and 0.012 Nm

a. $0.31{\text{Am}}^2;$ b. 0.16 Nm

$0.024{\text{Am}}^2$

a. $0.16{\text{Am}}^2;$ b. 0.016 Nm; c. 0.028 J

(Proof)

$4.65\times {10}^{\mathrm{-7}}\text{V}$

Since $E=Blv,$ where the width is twice the radius, $I=2r,$ $I=nqA{v}_d,$
$v_{\text{d}}=\frac{I}{nqA}=\frac{I}{nq\pi r^2}$ so $E=B\times 2r\times \frac{\text{I}}{nq\pi r^2}=\frac{2IB}{nq\pi r}\propto \frac{1}{r}\propto \frac{1}{d}.$
The Hall voltage is inversely proportional to the diameter of the wire.

$6.92\times {10}^7\text{m/s};$ 0.602 m

a. $2.4\times {10}^{\mathrm{-19}}\text{C};$ b. not an integer multiple of e; c. need to assume all charges have multiples of e, could be other forces not accounted for

a. B = 5 T; b. very large magnet; c. applying such a large voltage

$R=(mv\text{sin}\theta )\text{/}qB;$ $p=\left(\frac{2\pi m}{eB}\right)v\text{cos}\theta$

$Ia{L}^2\text{/}2$

$m=\frac{q{B}_0{}^2}{8V_{\text{acc}}}{x}^2$

0.23 N