Calculus Volume 3

# Review Exercises

Calculus Volume 3Review Exercises

### Review Exercises

True or False? Justify your answer with a proof or a counterexample.

117.

If $yy$ and $zz$ are both solutions to $y″+2y′+y=0,y″+2y′+y=0,$ then $y+zy+z$ is also a solution.

118.

The following system of algebraic equations has a unique solution:

$6 z 1 + 3 z 2 = 8 4 z 1 + 2 z 2 = 4 . 6 z 1 + 3 z 2 = 8 4 z 1 + 2 z 2 = 4 .$

119.

$y=excos(3x)+exsin(2x)y=excos(3x)+exsin(2x)$ is a solution to the second-order differential equation $y″+2y′+10=0.y″+2y′+10=0.$

120.

To find the particular solution to a second-order differential equation, you need one initial condition.

Classify the differential equation. Determine the order, whether it is linear and, if linear, whether the differential equation is homogeneous or nonhomogeneous. If the equation is second-order homogeneous and linear, find the characteristic equation.

121.

$y ″ − 2 y = 0 y ″ − 2 y = 0$

122.

$y ″ − 3 y + 2 y = cos ( t ) y ″ − 3 y + 2 y = cos ( t )$

123.

$( d y d t ) 2 + y y ′ = 1 ( d y d t ) 2 + y y ′ = 1$

124.

$d 2 y d t 2 + t d y d t + sin 2 ( t ) y = e t d 2 y d t 2 + t d y d t + sin 2 ( t ) y = e t$

For the following problems, find the general solution.

125.

$y ″ + 9 y = 0 y ″ + 9 y = 0$

126.

$y ″ + 2 y ′ + y = 0 y ″ + 2 y ′ + y = 0$

127.

$y ″ − 2 y ′ + 10 y = 4 x y ″ − 2 y ′ + 10 y = 4 x$

128.

$y ″ = cos ( x ) + 2 y ′ + y y ″ = cos ( x ) + 2 y ′ + y$

129.

$y ″ + 5 y + y = x + e 2 x y ″ + 5 y + y = x + e 2 x$

130.

$y ″ = 3 y ′ + x e − x y ″ = 3 y ′ + x e − x$

131.

$y ″ − x 2 = −3 y ′ − 9 4 y + 3 x y ″ − x 2 = −3 y ′ − 9 4 y + 3 x$

132.

$y ″ = 2 cos x + y ′ − y y ″ = 2 cos x + y ′ − y$

For the following problems, find the solution to the initial-value problem, if possible.

133.

$y″+4y′+6y=0,y″+4y′+6y=0,$ $y(0)=0,y(0)=0,$ $y′(0)=2y′(0)=2$

134.

$y″=3y−cos(x),y″=3y−cos(x),$ $y(0)=94,y(0)=94,$ $y′(0)=0y′(0)=0$

For the following problems, find the solution to the boundary-value problem.

135.

$4y′=−6y+2y″,4y′=−6y+2y″,$ $y(0)=0,y(0)=0,$ $y(1)=1y(1)=1$

136.

$y″=3x−y−y′,y″=3x−y−y′,$ $y(0)=−3,y(0)=−3,$ $y(1)=0y(1)=0$

For the following problem, set up and solve the differential equation.

137.

The motion of a swinging pendulum for small angles $θθ$ can be approximated by $d2θdt2+gLθ=0,d2θdt2+gLθ=0,$ where $θθ$ is the angle the pendulum makes with respect to a vertical line, g is the acceleration resulting from gravity, and L is the length of the pendulum. Find the equation describing the angle of the pendulum at time $t,t,$ assuming an initial displacement of $θ0θ0$ and an initial velocity of zero.

The following problems consider the “beats” that occur when the forcing term of a differential equation causes “slow” and “fast” amplitudes. Consider the general differential equation$ay″+by=cos(ωt)ay″+by=cos(ωt)$ that governs undamped motion. Assume that $ba≠ω.ba≠ω.$

138.

Find the general solution to this equation (Hint: call $ω0=b/aω0=b/a$).

139.

Assuming the system starts from rest, show that the particular solution can be written as $y=2a(ω02−ω2)sin(ω0−ωt2)sin(ω0+ωt2).y=2a(ω02−ω2)sin(ω0−ωt2)sin(ω0+ωt2).$

140.

[T] Using your solutions derived earlier, plot the solution to the system $2y″+9y=cos(2t)2y″+9y=cos(2t)$ over the interval $t=[−50,50].t=[−50,50].$ Find, analytically, the period of the fast and slow amplitudes.

For the following problem, set up and solve the differential equations.

141.

An opera singer is attempting to shatter a glass by singing a particular note. The vibrations of the glass can be modeled by $y″+ay=cos(bt),y″+ay=cos(bt),$ where $y″+ay=0y″+ay=0$ represents the natural frequency of the glass and the singer is forcing the vibrations at $cos(bt).cos(bt).$ For what value $bb$ would the singer be able to break that glass? (Note: in order for the glass to break, the oscillations would need to get higher and higher.)

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