8.1 Non-right Triangles: Law of Sines
- The Law of Sines can be used to solve oblique triangles, which are non-right triangles.
- According to the Law of Sines, the ratio of the measurement of one of the angles to the length of its opposite side equals the other two ratios of angle measure to opposite side.
- There are three possible cases: ASA, AAS, SSA. Depending on the information given, we can choose the appropriate equation to find the requested solution. See Example 1.
- The ambiguous case arises when an oblique triangle can have different outcomes.
- There are three possible cases that arise from SSA arrangement—a single solution, two possible solutions, and no solution. See Example 2 and Example 3.
- The Law of Sines can be used to solve triangles with given criteria. See Example 4.
- The general area formula for triangles translates to oblique triangles by first finding the appropriate height value. See Example 5.
- There are many trigonometric applications. They can often be solved by first drawing a diagram of the given information and then using the appropriate equation. See Example 6.
8.2 Non-right Triangles: Law of Cosines
- The Law of Cosines defines the relationship among angle measurements and lengths of sides in oblique triangles.
- The Generalized Pythagorean Theorem is the Law of Cosines for two cases of oblique triangles: SAS and SSS. Dropping an imaginary perpendicular splits the oblique triangle into two right triangles or forms one right triangle, which allows sides to be related and measurements to be calculated. See Example 1 and Example 2.
- The Law of Cosines is useful for many types of applied problems. The first step in solving such problems is generally to draw a sketch of the problem presented. If the information given fits one of the three models (the three equations), then apply the Law of Cosines to find a solution. See Example 3 and Example 4.
- Heron’s formula allows the calculation of area in oblique triangles. All three sides must be known to apply Heron’s formula. See Example 5 and See Example 6.
8.3 Polar Coordinates
- The polar grid is represented as a series of concentric circles radiating out from the pole, or origin.
- To plot a point in the formmove in a counterclockwise direction from the polar axis by an angle of and then extend a directed line segment from the pole the length of in the direction of Ifis negative, move in a clockwise direction, and extend a directed line segment the length of in the direction of See Example 1.
- Ifis negative, extend the directed line segment in the opposite direction ofSee Example 2.
- To convert from polar coordinates to rectangular coordinates, use the formulasandSee Example 3 and Example 4.
- To convert from rectangular coordinates to polar coordinates, use one or more of the formulas:andSee Example 5.
- Transforming equations between polar and rectangular forms means making the appropriate substitutions based on the available formulas, together with algebraic manipulations. See Example 6, Example 7, and Example 8.
- Using the appropriate substitutions makes it possible to rewrite a polar equation as a rectangular equation, and then graph it in the rectangular plane. See Example 9, Example 10, and Example 11.
8.4 Polar Coordinates: Graphs
- It is easier to graph polar equations if we can test the equations for symmetry with respect to the linethe polar axis, or the pole.
- There are three symmetry tests that indicate whether the graph of a polar equation will exhibit symmetry. If an equation fails a symmetry test, the graph may or may not exhibit symmetry. See Example 1.
- Polar equations may be graphed by making a table of values forand
- The maximum value of a polar equation is found by substituting the valuethat leads to the maximum value of the trigonometric expression.
- The zeros of a polar equation are found by settingand solving forSee Example 2.
- Some formulas that produce the graph of a circle in polar coordinates are given byandSee Example 3.
- The formulas that produce the graphs of a cardioid are given byandforandSee Example 4.
- The formulas that produce the graphs of a one-loop limaçon are given byandforSee Example 5.
- The formulas that produce the graphs of an inner-loop limaçon are given byandfor and See Example 6.
- The formulas that produce the graphs of a lemniscates are given byandwhereSee Example 7.
- The formulas that produce the graphs of rose curves are given byandwhereifis even, there arepetals, and ifis odd, there arepetals. See Example 8 and Example 9.
- The formula that produces the graph of an Archimedes’ spiral is given bySee Example 10.
8.5 Polar Form of Complex Numbers
- Complex numbers in the formare plotted in the complex plane similar to the way rectangular coordinates are plotted in the rectangular plane. Label the x-axis as the real axis and the y-axis as the imaginary axis. See Example 1.
- The absolute value of a complex number is the same as its magnitude. It is the distance from the origin to the point:See Example 2 and Example 3.
- To write complex numbers in polar form, we use the formulasand Then,See Example 4 and Example 5.
- To convert from polar form to rectangular form, first evaluate the trigonometric functions. Then, multiply through bySee Example 6 and Example 7.
- To find the product of two complex numbers, multiply the two moduli and add the two angles. Evaluate the trigonometric functions, and multiply using the distributive property. See Example 8.
- To find the quotient of two complex numbers in polar form, find the quotient of the two moduli and the difference of the two angles. See Example 9.
- To find the power of a complex numberraise to the power and multiply by See Example 10.
- Finding the roots of a complex number is the same as raising a complex number to a power, but using a rational exponent. See Example 11.
8.6 Parametric Equations
- Parameterizing a curve involves translating a rectangular equation in two variables,andinto two equations in three variables, x, y, and t. Often, more information is obtained from a set of parametric equations. See Example 1, Example 2, and Example 3.
- Sometimes equations are simpler to graph when written in rectangular form. By eliminatingan equation inandis the result.
- To eliminatesolve one of the equations forand substitute the expression into the second equation. See Example 4, Example 5, Example 6, and Example 7.
- Finding the rectangular equation for a curve defined parametrically is basically the same as eliminating the parameter. Solve forin one of the equations, and substitute the expression into the second equation. See Example 8.
- There are an infinite number of ways to choose a set of parametric equations for a curve defined as a rectangular equation.
- Find an expression forsuch that the domain of the set of parametric equations remains the same as the original rectangular equation. See Example 9.
8.7 Parametric Equations: Graphs
- When there is a third variable, a third parameter on whichanddepend, parametric equations can be used.
- To graph parametric equations by plotting points, make a table with three columns labeledandChoose values forin increasing order. Plot the last two columns forandSee Example 1 and Example 2.
- When graphing a parametric curve by plotting points, note the associated t-values and show arrows on the graph indicating the orientation of the curve. See Example 3 and Example 4.
- Parametric equations allow the direction or the orientation of the curve to be shown on the graph. Equations that are not functions can be graphed and used in many applications involving motion. See Example 5.
- Projectile motion depends on two parametric equations:andInitial velocity is symbolized as represents the initial angle of the object when thrown, and represents the height at which the object is propelled.
- The position vector has its initial point at the origin. See Example 1.
- If the position vector is the same for two vectors, they are equal. See Example 2.
- Vectors are defined by their magnitude and direction. See Example 3.
- If two vectors have the same magnitude and direction, they are equal. See Example 4.
- Vector addition and subtraction result in a new vector found by adding or subtracting corresponding elements. See Example 5.
- Scalar multiplication is multiplying a vector by a constant. Only the magnitude changes; the direction stays the same. See Example 6 and Example 7.
- Vectors are comprised of two components: the horizontal component along the positive x-axis, and the vertical component along the positive y-axis. See Example 8.
- The unit vector in the same direction of any nonzero vector is found by dividing the vector by its magnitude.
- The magnitude of a vector in the rectangular coordinate system isSee Example 9.
- In the rectangular coordinate system, unit vectors may be represented in terms of and whererepresents the horizontal component andrepresents the vertical component. Then, v = ai + bj is a scalar multiple ofby real numbersSee Example 10 and Example 11.
- Adding and subtracting vectors in terms of i and j consists of adding or subtracting corresponding coefficients of i and corresponding coefficients of j. See Example 12.
- A vector v = ai + bj is written in terms of magnitude and direction asSee Example 13.
- The dot product of two vectors is the product of theterms plus the product of theterms. See Example 14.
- We can use the dot product to find the angle between two vectors. Example 15 and Example 16.
- Dot products are useful for many types of physics applications. See Example 17.