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Calculus Volume 2

Key Concepts

Calculus Volume 2Key Concepts

Key Concepts

5.1 Sequences

  • To determine the convergence of a sequence given by an explicit formula an=f(n),an=f(n), we use the properties of limits for functions.
  • If {an}{an} and {bn}{bn} are convergent sequences that converge to AA and B,B, respectively, and cc is any real number, then the sequence {can}{can} converges to c·A,c·A, the sequences {an±bn}{an±bn} converge to A±B,A±B, the sequence {an·bn}{an·bn} converges to A·B,A·B, and the sequence {an/bn}{an/bn} converges to A/B,A/B, provided B≠0.B≠0.
  • If a sequence is bounded and monotone, then it converges, but not all convergent sequences are monotone.
  • If a sequence is unbounded, it diverges, but not all divergent sequences are unbounded.
  • The geometric sequence {rn}{rn} converges if and only if |r|<1|r|<1 or r=1.r=1.

5.2 Infinite Series

  • Given the infinite series
    ∑n=1∞an=a1+a2+a3+⋯∑n=1∞an=a1+a2+a3+⋯

    and the corresponding sequence of partial sums {Sk}{Sk} where
    Sk=∑n=1kan=a1+a2+a3+⋯+ak,Sk=∑n=1kan=a1+a2+a3+⋯+ak,

    the series converges if and only if the sequence {Sk}{Sk} converges.
  • The geometric series ∑n=1∞arn−1∑n=1∞arn−1 converges if |r|<1|r|<1 and diverges if |r|≥1.|r|≥1. For |r|<1,|r|<1,
    ∑n=1∞arn−1=a1−r.∑n=1∞arn−1=a1−r.
  • The harmonic series
    ∑n=1∞1n=1+12+13+⋯∑n=1∞1n=1+12+13+⋯

    diverges.
  • A series of the form ∑n=1∞[bn−bn+1]=[b1−b2]+[b2−b3]+[b3−b4]+⋯+[bn−bn+1]+⋯∑n=1∞[bn−bn+1]=[b1−b2]+[b2−b3]+[b3−b4]+⋯+[bn−bn+1]+⋯
    is a telescoping series. The kthkth partial sum of this series is given by Sk=b1−bk+1.Sk=b1−bk+1. The series will converge if and only if limk→∞bk+1limk→∞bk+1 exists. In that case,
    ∑n=1∞[bn−bn+1]=b1−limk→∞(bk+1).∑n=1∞[bn−bn+1]=b1−limk→∞(bk+1).

5.3 The Divergence and Integral Tests

  • If limn→∞an≠0,limn→∞an≠0, then the series ∑n=1∞an∑n=1∞an diverges.
  • If limn→∞an=0,limn→∞an=0, the series ∑n=1∞an∑n=1∞an may converge or diverge.
  • If ∑n=1∞an∑n=1∞an is a series with positive terms anan and ff is a continuous, decreasing function such that f(n)=anf(n)=an for all positive integers n,n, then
    ∑n=1∞anand∫1∞f(x)dx∑n=1∞anand∫1∞f(x)dx

    either both converge or both diverge. Furthermore, if ∑n=1∞an∑n=1∞an converges, then the NthNth partial sum approximation SNSN is accurate up to an error RNRN where ∫N+1∞f(x)dx<RN<∫N∞f(x)dx.∫N+1∞f(x)dx<RN<∫N∞f(x)dx.
  • The p-series ∑n=1∞1/np∑n=1∞1/np converges if p>1p>1 and diverges if p≤1.p≤1.

5.4 Comparison Tests

  • The comparison tests are used to determine convergence or divergence of series with positive terms.
  • When using the comparison tests, a series ∑n=1∞an∑n=1∞an is often compared to a geometric or p-series.

5.5 Alternating Series

  • For an alternating series ∑n=1∞(−1)n+1bn,∑n=1∞(−1)n+1bn, if bk+1≤bkbk+1≤bk for all kk and bk→0bk→0 as k→∞,k→∞, the alternating series converges.
  • If ∑n=1∞|an|∑n=1∞|an| converges, then ∑n=1∞an∑n=1∞an converges.

5.6 Ratio and Root Tests

  • For the ratio test, we consider
    ρ=limn→∞|an+1an|.ρ=limn→∞|an+1an|.

    If ρ<1,ρ<1, the series ∑n=1∞an∑n=1∞an converges absolutely. If ρ>1,ρ>1, the series diverges. If ρ=1,ρ=1, the test does not provide any information. This test is useful for series whose terms involve factorials.
  • For the root test, we consider
    ρ=limn→∞|an|n.ρ=limn→∞|an|n.

    If ρ<1,ρ<1, the series ∑n=1∞an∑n=1∞an converges absolutely. If ρ>1,ρ>1, the series diverges. If ρ=1,ρ=1, the test does not provide any information. The root test is useful for series whose terms involve powers.
  • For a series that is similar to a geometric series or p−series,p−series, consider one of the comparison tests.
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