8.11.4 • Writing Quadratics When Given Any Format
Cool Down
In this lesson, you have learned how to write a quadratic function from different starting contexts and when provided different information.
1 .
Identify a quadratic function in standard form,
b
(
x
)
b ( x ) , with the zeros –6 and 8.
Compare your answer:
b
(
x
)
=
x
2
−
2
x
−
48
b ( x ) =
x
2
− 2 x − 48
2 .
Identify a quadratic function in standard form,
m
(
x
)
m ( x ) , with the given zero.
Compare your answer:
m
(
x
)
=
x
2
−
12
x
+
36
m ( x ) =
x
2
− 12 x + 36
3 .
Write the specific quadratic function,
d
(
x
)
d ( x ) , in standard form, that has the zeros 2 and 5 and passes through the point
(
1
,
16
)
( 1 , 16 ) .
Compare your answer:
Intercept form:
d
(
x
)
=
a
(
x
−
2
)
(
x
−
5
)
d ( x ) = a ( x − 2 ) ( x − 5 )
Find the value of
a
a . Use point
(
1
,
16
)
( 1 , 16 ) .
d
(
x
)
=
a
(
x
−
2
)
(
x
−
5
)
d ( x ) = a ( x − 2 ) ( x − 5 )
16
=
a
(
(
1
)
−
2
)
(
(
1
)
−
5
)
16 = a ( ( 1 ) − 2 ) ( ( 1 ) − 5 )
16
=
a
(
−
1
)
(
−
4
)
16 = a ( − 1 ) ( − 4 )
16
=
4
a
16 = 4 a
4
=
a
4 = a
Substitute 4 for a a .
d
(
x
)
=
a
(
x
−
2
)
(
x
−
5
)
d ( x ) = a ( x − 2 ) ( x − 5 )
d
(
x
)
=
4
(
x
−
2
)
(
x
−
5
)
d ( x ) = 4 ( x − 2 ) ( x − 5 )
d
(
x
)
=
4
(
x
2
−
2
x
−
5
x
+
10
)
d ( x ) = 4 (
x
2
− 2 x − 5 x + 10 )
d
(
x
)
=
4
(
x
2
−
7
x
+
10
)
d ( x ) = 4 (
x
2
− 7 x + 10 )
d
(
x
)
=
4
x
2
−
28
x
+
40
d ( x ) = 4
x
2
− 28 x + 40
So, the specific quadratic function written in standard form is
d
(
x
)
=
4
x
2
−
28
x
+
40
d ( x ) = 4
x
2
− 28 x + 40 .