## Check Your Understanding

$3\phantom{\rule{0.2em}{0ex}}\times \phantom{\rule{0.2em}{0ex}}{10}^{4}\text{m}$ or 30 km. It is probably an underestimate because the density of the atmosphere decreases with altitude. (In fact, 30 km does not even get us out of the stratosphere.)

No, the coach’s new stopwatch will not be helpful. The uncertainty in the stopwatch is too great to differentiate between the sprint times effectively.

## Conceptual Questions

Physics is the science concerned with describing the interactions of energy, matter, space, and time to uncover the fundamental mechanisms that underlie every phenomenon.

No, neither of these two theories is more valid than the other. Experimentation is the ultimate decider. If experimental evidence does not suggest one theory over the other, then both are equally valid. A given physicist might prefer one theory over another on the grounds that one seems more simple, more natural, or more beautiful than the other, but that physicist would quickly acknowledge that he or she cannot say the other theory is invalid. Rather, he or she would be honest about the fact that more experimental evidence is needed to determine which theory is a better description of nature.

Conversions between units require factors of 10 only, which simplifies calculations. Also, the same basic units can be scaled up or down using metric prefixes to sizes appropriate for the problem at hand.

a. Base units are defined by a particular process of measuring a base quantity whereas derived units are defined as algebraic combinations of base units. b. A base quantity is chosen by convention and practical considerations. Derived quantities are expressed as algebraic combinations of base quantities. c. A base unit is a standard for expressing the measurement of a base quantity within a particular system of units. So, a measurement of a base quantity could be expressed in terms of a base unit in any system of units using the same base quantities. For example, length is a base quantity in both SI and the English system, but the meter is a base unit in the SI system only.

a. Uncertainty is a quantitative measure of precision. b. Discrepancy is a quantitative measure of accuracy.

## Problems

$1.05\phantom{\rule{0.2em}{0ex}}\times \phantom{\rule{0.2em}{0ex}}{10}^{5}{\phantom{\rule{0.2em}{0ex}}\text{ft}}^{2}$

a. $1.3\phantom{\rule{0.2em}{0ex}}\times \phantom{\rule{0.2em}{0ex}}{10}^{\mathrm{-9}}\text{m};$ b. 40 km/My

$3.6\phantom{\rule{0.2em}{0ex}}\times \phantom{\rule{0.2em}{0ex}}{10}^{\mathrm{-4}}{\text{m}}^{3}$

a. Yes, both terms have dimension L^{2}T^{-2} b. No. c. Yes, both terms have dimension LT^{-1} d. Yes, both terms have dimension LT^{-2}

a. [v] = LT^{–1}; b. [a] = LT^{–2}; c. $\left[{\displaystyle \int v}dt\right]=\text{L;}$ d. $\left[{\displaystyle \int a}dt\right]={\text{LT}}^{\mathrm{\u20131}}\text{;}$ e. $\left[\frac{da}{dt}\right]={\text{LT}}^{\mathrm{\u20133}}$

a. A reasonable estimate might be one operation per second for a total of 10^{9} in a lifetime.; b. about (10^{9})(10^{–17} s) = 10^{–8} s, or about 10 ns

a. The number 99 has 2 significant figures; 100. has 3 significant figures. b. 1.00%; c. percent uncertainties

a. 37.2 lb; because the number of bags is an exact value, it is not considered in the significant figures; b. 1.4 N; because the value 55 kg has only two significant figures, the final value must also contain two significant figures

## Additional Problems

a. $[{s}_{0}]=\text{L}$ and units are meters (m); b. $[{v}_{0}]={\text{LT}}^{\mathrm{-1}}$ and units are meters per second (m/s); c. $[{a}_{0}]={\text{LT}}^{\mathrm{-2}}$ and units are meters per second squared (m/s^{2}); d. $[{j}_{0}]={\text{LT}}^{\mathrm{-3}}$ and units are meters per second cubed (m/s^{3}); e. $[{S}_{0}]={\text{LT}}^{\mathrm{-4}}$ and units are m/s^{4}; f. $[c]={\text{LT}}^{\mathrm{-5}}$ and units are m/s^{5}.

## Challenge Problems

Since each term in the power series involves the argument raised to a different power, the only way that every term in the power series can have the same dimension is if the argument is dimensionless. To see this explicitly, suppose [x] = L^{a}M^{b}T^{c}. Then, [x^{n}] = [x]^{n} = L^{an}M^{bn}T^{cn}. If we want [x] = [x^{n}], then an = a, bn = b, and cn = c for all n. The only way this can happen is if a = b = c = 0.