For most of the work you do in this book, you will use a histogram to display the data. One advantage of a histogram is that it can readily display large data sets.

A histogram consists of contiguous (adjoining) boxes. It has both a horizontal axis and a vertical axis. The horizontal axis is more or less a number line, labeled with what the data represents, for example, distance from your home to school. The vertical axis is labeled either frequency or relative frequency (or percent frequency or probability). The graph will have the same shape with either label. The histogram (like the stemplot) can give you the shape of the data, the center, and the spread of the data. The shape of the data refers to the shape of the distribution, whether normal, approximately normal, or skewed in some direction, whereas the center is thought of as the middle of a data set, and the spread indicates how far the values are dispersed about the center. In a skewed distribution, the mean is pulled toward the tail of the distribution.

The relative frequency is equal to the frequency for an observed value of the data divided by the total number of data values in the sample. Remember, frequency is defined as the number of times an answer occurs. If

*f*= frequency,*n*= total number of data values (or the sum of the individual frequencies), and*RF*= relative frequency,

then

For example, if three students in Mr. Ahab's English class of 40 students received from ninety to 100 percent, then *f* = 3, *n* = 40, and *RF* = $\frac{f}{n}$ = $\frac{3}{40}$ = 0.075. Thus, 7.5 percent of the students received 90 to 100 percent. Ninety to 100 percent is a quantitative measures.

**To construct a histogram**, first decide how many **bars** or **intervals**, also called classes, represent the data. Many histograms consist of five to 15 bars or classes for clarity. The width of each bar is also referred to as the bin size, which may be calculated by dividing the range of the data values by the desired number of bins (or bars). There is not a set procedure for determining the number of bars or bar width/bin size; however, consistency is key when determining which data values to place inside each interval.

### Example 2.9

The following data are the heights (in inches to the nearest half inch) of 100 male semiprofessional soccer players. The heights are **continuous** data since height is measured.

60, 60.5, 61, 61, 61.5,

63.5, 63.5, 63.5,

64, 64, 64, 64, 64, 64, 64, 64.5, 64.5, 64.5, 64.5, 64.5, 64.5, 64.5, 64.5,

66, 66, 66, 66, 66, 66, 66, 66, 66, 66, 66.5, 66.5, 66.5, 66.5, 66.5, 66.5, 66.5, 66.5, 66.5, 66.5, 66.5, 67, 67, 67, 67, 67, 67, 67, 67, 67, 67, 67, 67, 67.5, 67.5, 67.5, 67.5, 67.5, 67.5, 67.5,

68, 68, 69, 69, 69, 69, 69, 69, 69, 69, 69, 69, 69.5, 69.5, 69.5, 69.5, 69.5,

70, 70, 70, 70, 70, 70, 70.5, 70.5, 70.5, 71, 71, 71,

72, 72, 72, 72.5, 72.5, 73, 73.5,

74

The smallest data value is 60, and the largest data value is 74. To make sure each is included in an interval, we can use 59.95 as the smallest value and 74.05 as the largest value, subtracting and adding .05 to these values, respectively. We have a small range here of 14.1 (74.05 – 59.95), so we will want a fewer number of bins; let’'s say eight. So, 14.1 divided by eight bins gives a bin size (or interval size) of approximately 1.76.

### NOTE

We will round up to two and make each bar or class interval two units wide. Rounding up to two is a way to prevent a value from falling on a boundary. Rounding to the next number is often necessary even if it goes against the standard rules of rounding. For this example, using 1.76 as the width would also work. A guideline that is followed by some for the width of a bar or class interval is to take the square root of the number of data values and then round to the nearest whole number, if necessary. For example, if there are 150 values of data, take the square root of 150 and round to 12 bars or intervals.

The boundaries are as follows:

- 59.95
- 59.95 + 2 = 61.95
- 61.95 + 2 = 63.95
- 63.95 + 2 = 65.95
- 65.95 + 2 = 67.95
- 67.95 + 2 = 69.95
- 69.95 + 2 = 71.95
- 71.95 + 2 = 73.95
- 73.95 + 2 = 75.95

The heights 60 through 61.5 inches are in the interval 59.95–61.95. The heights that are 63.5 are in the interval 61.95–63.95. The heights that are 64 through 64.5 are in the interval 63.95–65.95. The heights 66 through 67.5 are in the interval 65.95–67.95. The heights 68 through 69.5 are in the interval 67.95–69.95. The heights 70 through 71 are in the interval 69.95–71.95. The heights 72 through 73.5 are in the interval 71.95–73.95. The height 74 is in the interval 73.95–75.95.

The following histogram displays the heights on the *x*-axis and relative frequency on the *y*-axis.

Interval | Frequency | Relative Frequency |
---|---|---|

59.95–61.95 | 5 | 5/100 = 0.05 |

61.95–63.95 | 3 | 3/100 = 0.03 |

63.95–65.95 | 15 | 15/100 = 0.15 |

65.95–67.95 | 40 | 40/100 = 0.40 |

67.95–69.95 | 17 | 17/100 = 0.17 |

69.95–71.95 | 12 | 12/100 = 0.12 |

71.95–73.95 | 7 | 7/100 = 0.07 |

73.95–75.95 | 1 | 1/100 = 0.01 |

The following data are the shoe sizes of 50 male students. The sizes are continuous data since shoe size is measured. Construct a histogram and calculate the width of each bar or class interval. Use six bars on the histogram.

9, 9, 9.5, 9.5, 10, 10, 10, 10, 10, 10, 10.5, 10.5, 10.5, 10.5, 10.5, 10.5, 10.5, 10.5,

11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11.5, 11.5, 11.5, 11.5, 11.5, 11.5, 11.5,

12, 12, 12, 12, 12, 12, 12, 12.5, 12.5, 12.5, 12.5, 14

### Example 2.10

The following data are the number of books bought by 50 part-time college students at ABC College. The number of books is **discrete data** since books are counted.

1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,

2, 2, 2, 2, 2, 2, 2, 2, 2, 2,

3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3,

4, 4, 4, 4, 4, 4,

5, 5, 5, 5, 5,

6, 6

Eleven students buy one book. Ten students buy two books. Sixteen students buy three books. Six students buy four books. Five students buy five books. Two students buy six books.

Calculate the width of each bar/bin size/interval size.

Notice that we may choose different rational numbers to add to, or subtract from, our maximum and minimum values when calculating bin size. In the previous example, we added and subtracted .05, while this time, we added and subtracted .5. Given a data set, you will be able to determine what is appropriate and reasonable.

The following histogram displays the number of books on the *x*-axis and the frequency on the *y*-axis.

### Using the TI-83, 83+, 84, 84+ Calculator

Go to Appendix G. There are calculator instructions for entering data and for creating a customized histogram. Create the histogram for Example 2.10.

- Press Y=. Press CLEAR to delete any equations.
- Press STAT 1:EDIT. If L1 has data in it, arrow up into the name L1, press CLEAR and then arrow down. If necessary, do the same for L2.
- Into L1, enter 1, 2, 3, 4, 5, 6. Note that these values represent the numbers of books.
- Into L2, enter 11, 10, 16, 6, 5, 2. Note that these numbers represent the frequencies for the numbers of books.
- Press WINDOW. Set Xmin = .5, Xscl = (6.5 – .5)/6, Ymin = –1, Ymax = 20, Yscl = 1, Xres = 1. The window settings are chosen to accurately and completely show the data value range and the frequency range.
- Press second Y=. Start by pressing 4:Plotsoff ENTER.
- Press second Y=. Press 1:Plot1. Press ENTER. Arrow down to TYPE. Arrow to the third picture (histogram). Press ENTER.
- Arrow down to Xlist: Enter L1 (2
^{nd}1). Arrow down to Freq. Enter L2 (second 2). - Press GRAPH.
- Use the TRACE key and the arrow keys to examine the histogram.

The following data are the number of sports played by 50 student athletes. The number of sports is discrete data since sports are counted.

1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,

2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,

3, 3, 3, 3, 3, 3, 3, 3

Twenty student athletes play one sport. Twenty-two student athletes play two sports. Eight student athletes play three sports. Calculate a desired bin size for the data. Create a histogram and clearly label the endpoints of the intervals.

### Example 2.11

Using this data set, construct a histogram.

Number of Hours My Classmates Spent Playing Video Games on Weekends | ||||
---|---|---|---|---|

9.95 | 10 | 2.25 | 16.75 | 0 |

19.5 | 22.5 | 7.5 | 15 | 12.75 |

5.5 | 11 | 10 | 20.75 | 17.5 |

23 | 21.9 | 24 | 23.75 | 18 |

20 | 15 | 22.9 | 18.8 | 20.5 |

The following data represent the number of employees at various restaurants in New York City. Using this data, create a histogram.

22, 35, 15, 26, 40, 28, 18, 20, 25, 34, 39, 42, 24, 22, 19, 27, 22, 34, 40, 20, 38, 28

### Collaborative Exercise

Count the money (bills and change) in your pocket or purse. Your instructor will record the amounts. As a class, construct a histogram displaying the data. Discuss how many intervals you think would be appropriate. You may want to experiment with the number of intervals.

### Frequency Polygons

Frequency polygons are analogous to line graphs, and just as line graphs make continuous data visually easy to interpret, so too do frequency polygons.

To construct a frequency polygon, first examine the data and decide on the number of intervals and resulting interval size, for both the *x*-axis and *y*-axis. The *x*-axis will show the lower and upper bound for each interval, containing the data values, whereas the *y*-axis will represent the frequencies of the values. Each data point represents the frequency for each interval. For example, if an interval has three data values in it, the frequency polygon will show a 3 at the upper endpoint of that interval. After choosing the appropriate intervals, begin plotting the data points. After all the points are plotted, draw line segments to connect them.

### Example 2.12

A frequency polygon was constructed from the frequency table below.

Frequency Distribution for Calculus Final Test Scores | |||
---|---|---|---|

Lower Bound | Upper Bound | Frequency | Cumulative Frequency |

49.5 | 59.5 | 5 | 5 |

59.5 | 69.5 | 10 | 15 |

69.5 | 79.5 | 30 | 45 |

79.5 | 89.5 | 40 | 85 |

89.5 | 99.5 | 15 | 100 |

Notice that each point represents frequency for a particular interval. These points are located halfway between the lower bound and upper bound. In fact, the horizontal axis, or *x*-axis, shows only these midpoint values. For the interval 49.5–59.5 the value 54.5 is represented by a point, showing the correct frequency of 5. For the interval occurring before 49.5–59.5, (as well as 39.5–49.5), the value of the midpoint, or 44.5, is represented by a point, showing a frequency of 0, since we do not have any values in that range. The same idea applies to the last interval of 99.5–109.5, which has a midpoint of 104.5 and correctly shows a point representing a frequency of 0. Looking at the graph, we say
that this distribution is skewed because one side of the graph does not mirror the other side.

Construct a frequency polygon of U.S. presidents’ ages at inauguration shown in Table 2.18.

Age at Inauguration | Frequency |
---|---|

41.5–46.5 | 4 |

46.5–51.5 | 11 |

51.5–56.5 | 14 |

56.5–61.5 | 9 |

61.5–66.5 | 4 |

66.5–71.5 | 2 |

Frequency polygons are useful for comparing distributions. This comparison is achieved by overlaying the frequency polygons drawn for different data sets.

### Example 2.13

We will construct an overlay frequency polygon comparing the scores from Example 2.12 with the students’ final numeric grades.

Frequency Distribution for Calculus Final Test Scores | |||
---|---|---|---|

Lower Bound | Upper Bound | Frequency | Cumulative Frequency |

49.5 | 59.5 | 5 | 5 |

59.5 | 69.5 | 10 | 15 |

69.5 | 79.5 | 30 | 45 |

79.5 | 89.5 | 40 | 85 |

89.5 | 99.5 | 15 | 100 |

Frequency Distribution for Calculus Final Grades | |||
---|---|---|---|

Lower Bound | Upper Bound | Frequency | Cumulative Frequency |

49.5 | 59.5 | 10 | 10 |

59.5 | 69.5 | 10 | 20 |

69.5 | 79.5 | 30 | 50 |

79.5 | 89.5 | 45 | 95 |

89.5 | 99.5 | 5 | 100 |

Suppose that we want to study the temperature range of a region for an entire month. Every day at noon, we note the temperature and write this down in a log. A variety of statistical studies could be done with these data. We could find the mean or the median temperature for the month. We could construct a histogram displaying the number of days that temperatures reach a certain range of values. However, all of these methods ignore a portion of the data that we have collected.

One feature of the data that we may want to consider is that of time. Since each date is paired with the temperature reading for the day, we don't have to think of the data as being random. We can instead use the times given to impose a chronological order on the data. A graph that recognizes this ordering and displays the changing temperature as the month progresses is called a time series graph.

### Constructing a Time Series Graph

To construct a time series graph, we must look at both pieces of our paired data set. We start with a standard Cartesian coordinate system. The horizontal axis is used to plot the date or time increments, and the vertical axis is used to plot the values of the variable that we are measuring. By using the axes in that way, we make each point on the graph correspond to a date and a measured quantity. The points on the graph are typically connected by straight lines in the order in which they occur.

### Example 2.14

The following data show the Annual Consumer Price Index each month for 10 years. Construct a time series graph for the Annual Consumer Price Index data only.

Year | Jan | Feb | Mar | Apr | May | Jun | Jul |
---|---|---|---|---|---|---|---|

2003 |
181.7 | 183.1 | 184.2 | 183.8 | 183.5 | 183.7 | 183.9 |

2004 |
185.2 | 186.2 | 187.4 | 188.0 | 189.1 | 189.7 | 189.4 |

2005 |
190.7 | 191.8 | 193.3 | 194.6 | 194.4 | 194.5 | 195.4 |

2006 |
198.3 | 198.7 | 199.8 | 201.5 | 202.5 | 202.9 | 203.5 |

2007 |
202.416 | 203.499 | 205.352 | 206.686 | 207.949 | 208.352 | 208.299 |

2008 |
211.080 | 211.693 | 213.528 | 214.823 | 216.632 | 218.815 | 219.964 |

2009 |
211.143 | 212.193 | 212.709 | 213.240 | 213.856 | 215.693 | 215.351 |

2010 |
216.687 | 216.741 | 217.631 | 218.009 | 218.178 | 217.965 | 218.011 |

2011 |
220.223 | 221.309 | 223.467 | 224.906 | 225.964 | 225.722 | 225.922 |

2012 |
226.665 | 227.663 | 229.392 | 230.085 | 229.815 | 229.478 | 229.104 |

Year | Aug | Sep | Oct | Nov | Dec | Annual |
---|---|---|---|---|---|---|

2003 |
184.6 | 185.2 | 185.0 | 184.5 | 184.3 | 184.0 |

2004 |
189.5 | 189.9 | 190.9 | 191.0 | 190.3 | 188.9 |

2005 |
196.4 | 198.8 | 199.2 | 197.6 | 196.8 | 195.3 |

2006 |
203.9 | 202.9 | 201.8 | 201.5 | 201.8 | 201.6 |

2007 |
207.917 | 208.490 | 208.936 | 210.177 | 210.036 | 207.342 |

2008 |
219.086 | 218.783 | 216.573 | 212.425 | 210.228 | 215.303 |

2009 |
215.834 | 215.969 | 216.177 | 216.330 | 215.949 | 214.537 |

2010 |
218.312 | 218.439 | 218.711 | 218.803 | 219.179 | 218.056 |

2011 |
226.545 | 226.889 | 226.421 | 226.230 | 225.672 | 224.939 |

2012 |
230.379 | 231.407 | 231.317 | 230.221 | 229.601 | 229.594 |

The following table is a portion of a data set from a banking website. Use the table to construct a time series graph for CO_{2} emissions for the United States.

CO_{2} Emissions |
|||
---|---|---|---|

Ukraine | United Kingdom | United States | |

2003 | 352,259 | 540,640 | 5,681,664 |

2004 | 343,121 | 540,409 | 5,790,761 |

2005 | 339,029 | 541,990 | 5,826,394 |

2006 | 327,797 | 542,045 | 5,737,615 |

2007 | 328,357 | 528,631 | 5,828,697 |

2008 | 323,657 | 522,247 | 5,656,839 |

2009 | 272,176 | 474,579 | 5,299,563 |

#### Uses of a Time Series Graph

Time series graphs are important tools in various applications of statistics. When a researcher records values of the same variable over an extended period of time, it is sometimes difficult for him or her to discern any trend or pattern. However, once the same data points are displayed graphically, some features jump out. Time series graphs make trends easy to spot.