### Learning Objectives

By the end of this section, you will be able to:

- Simplify expressions with absolute value
- Add and subtract integers
- Multiply and divide integers
- Simplify expressions with integers
- Evaluate variable expressions with integers
- Translate phrases to expressions with integers
- Use integers in applications

### Be Prepared 1.2

A more thorough introduction to the topics covered in this section can be found in the *Elementary Algebra 2e* chapter, Foundations.

### Simplify Expressions with Absolute Value

A negative number is a number less than 0. The negative numbers are to the left of zero on the number line. See Figure 1.2.

You may have noticed that, on the number line, the negative numbers are a mirror image of the positive numbers, with zero in the middle. Because the numbers $2$ and $\mathrm{-2}$ are the same distance from zero, each one is called the opposite of the other. The opposite of $2$ is $\mathrm{-2},$ and the opposite of $\mathrm{-2}$ is $2.$

### Opposite

The **opposite** of a number is the number that is the same distance from zero on the number line but on the opposite side of zero.

Figure 1.3 illustrates the definition.

### Opposite Notation

We saw that numbers such as 3 and $\mathrm{-3}$ are opposites because they are the same distance from 0 on the number line. They are both three units from 0. The distance between 0 and any number on the number line is called the absolute value of that number.

### Absolute Value

The **absolute value** of a number is its distance from 0 on the number line.

The absolute value of a number $n$ is written as $\left|n\right|$ and $\left|n\right|\ge 0$ for all numbers.

Absolute values are always greater than or equal to zero.

For example,

Figure 1.4 illustrates this idea.

The absolute value of a number is never negative because distance cannot be negative. The only number with absolute value equal to zero is the number zero itself because the distance from 0 to 0 on the number line is zero units.

In the next example, we’ll order expressions with absolute values.

### Example 1.12

Fill in $<,>,$ or $=$ for each of the following pairs of numbers:

ⓐ $\left|\mathrm{-5}\right|\_\_-\left|\mathrm{-5}\right|$ ⓑ $8\_\_-\left|\mathrm{-8}\right|$ ⓒ $\mathrm{-9}\_\_-\left|\mathrm{-9}\right|$ ⓓ $\text{\u2212}\left(\mathrm{-16}\right)\_\_\left|\mathrm{-16}\right|.$

#### Solution

ⓐ

$\left|\mathrm{-5}\right|\_\_-\left|\mathrm{-5}\right|$ | |

Simplify. | $\phantom{\rule{1.3em}{0ex}}5\_\_-5$ |

Order. | $\phantom{\rule{1.3em}{0ex}}5>-5$ |

$\left|\mathrm{-5}\right|>-\left|\mathrm{-5}\right|$ |

ⓑ

$8\_\_-\left|\mathrm{-8}\right|$ | |

Simplify. | $8\_\_-8$ |

Order. | $8>-8$ |

$8>-\left|\mathrm{-8}\right|$ |

ⓒ

$\mathrm{-9}\_\_-\left|\mathrm{-9}\right|$ | |

Simplify. | $\mathrm{-9}\_\_\mathrm{-9}$ |

Order. | $\mathrm{-9}=\mathrm{-9}$ |

$\mathrm{-9}=-\left|\mathrm{-9}\right|$ |

ⓓ

$-\left(\mathrm{-16}\right)\_\_\left|\mathrm{-16}\right|$ | |

Simplify. | $\phantom{\rule{2.3em}{0ex}}16\_\_16$ |

Order. | $\phantom{\rule{2.3em}{0ex}}16=16$ |

$-\left(\mathrm{-16}\right)=\left|\mathrm{-16}\right|$ |

### Try It 1.23

Fill in $<,>,$ or $=$ for each of the following pairs of numbers:

ⓐ $\mathrm{-9}\_\_-\left|\mathrm{-9}\right|$ ⓑ $2\_\_-\left|\mathrm{-2}\right|$ ⓒ $\mathrm{-8}\_\_\left|\mathrm{-8}\right|$ ⓓ $\text{\u2212}\left(\mathrm{-9}\right)\_\_\left|\mathrm{-9}\right|.$

### Try It 1.24

Fill in $<,>,$ or $=$ for each of the following pairs of numbers:

ⓐ $7\_\_-\left|\mathrm{-7}\right|$ ⓑ $\text{\u2212}\left(\mathrm{-10}\right)\_\_\left|\mathrm{-10}\right|$ ⓒ $\left|\mathrm{-4}\right|\_\_-\left|\mathrm{-4}\right|$ ⓓ $\mathrm{-1}\_\_\left|\mathrm{-1}\right|.$

We now add absolute value bars to our list of grouping symbols. When we use the order of operations, first we simplify inside the absolute value bars as much as possible, then we take the absolute value of the resulting number.

### Grouping Symbols

In the next example, we simplify the expressions inside absolute value bars first just as we do with parentheses.

### Example 1.13

Simplify: $24-\left|19-3\left(6-2\right)\right|.$

#### Solution

$24-\left|19-3\left(6-2\right)\right|$ | |

Work inside parentheses first: | |

subtract 2 from 6. | $24-\left|19-3\left(4\right)\right|$ |

Multiply 3(4). | $24-\left|19-12\right|$ |

Subtract inside the absolute value bars. | $24-\left|7\right|$ |

Take the absolute value. | $24-7$ |

Subtract. | $17$ |

### Try It 1.25

Simplify:$19-\left|11-4\left(3-1\right)\right|.$

### Try It 1.26

Simplify: $9-\left|8-4\left(7-5\right)\right|.$

### Add and Subtract Integers

So far, we have only used the counting numbers and the whole numbers.

Our work with opposites gives us a way to define the integers. The whole numbers and their opposites are called the integers. The integers are the numbers $\dots \mathrm{-3},\mathrm{-2},\mathrm{-1},0,1,2,3\text{\u2026}$

### Integers

The whole numbers and their opposites are called the **integers**.

The integers are the numbers

Most students are comfortable with the addition and subtraction facts for positive numbers. But doing addition or subtraction with both positive and negative numbers may be more challenging.

We will use two color counters to model addition and subtraction of negatives so that you can visualize the procedures instead of memorizing the rules.

We let one color (blue) represent positive. The other color (red) will represent the negatives.

If we have one positive counter and one negative counter, the value of the pair is zero. They form a neutral pair. The value of this neutral pair is zero.

We will use the counters to show how to add:

The first example, $5+3,$ adds 5 positives and 3 positives—both positives.

The second example, $\mathrm{-5}+\left(\mathrm{-3}\right),$ adds 5 negatives and 3 negatives—both negatives.

When the signs are the same, the counters are all the same color, and so we add them. In each case we get 8—either 8 positives or 8 negatives.

So what happens when the signs are different? Let’s add $\mathrm{-5}+3$ and $5+\left(\mathrm{-3}\right).$

When we use counters to model addition of positive and negative integers, it is easy to see whether there are more positive or more negative counters. So we know whether the sum will be positive or negative.

### Example 1.14

Add: ⓐ $\mathrm{-1}+\left(\mathrm{-4}\right)$ ⓑ $\mathrm{-1}+5$ ⓒ $1+\left(\mathrm{-5}\right).$

#### Solution

ⓐ

1 negative plus 4 negatives is 5 negatives |

ⓑ

There are more positives, so the sum is positive. |

ⓒ

There are more negatives, so the sum is negative. |

### Try It 1.27

Add: ⓐ $\mathrm{-2}+\left(\mathrm{-4}\right)$ ⓑ $\mathrm{-2}+4$ ⓒ $2+\left(\mathrm{-4}\right).$

### Try It 1.28

Add: ⓐ $\mathrm{-2}+\left(\mathrm{-5}\right)$ ⓑ $\mathrm{-2}+5$ ⓒ $2+\left(\mathrm{-5}\right).$

We will continue to use counters to model the subtraction. Perhaps when you were younger, you read $\u201c5-3\u201d$ as “5 take away 3.” When you use counters, you can think of subtraction the same way!

We will use the counters to show to subtract:

The first example, $5-3,$ we subtract 3 positives from 5 positives and end up with 2 positives.

In the second example, $\mathrm{-5}-\left(\mathrm{-3}\right),$ we subtract 3 negatives from 5 negatives and end up with 2 negatives.

Each example used counters of only one color, and the “take away” model of subtraction was easy to apply.

What happens when we have to subtract one positive and one negative number? We’ll need to use both blue and red counters as well as some neutral pairs. If we don’t have the number of counters needed to take away, we add neutral pairs. Adding a neutral pair does not change the value. It is like changing quarters to nickels—the value is the same, but it looks different.

Let’s look at $\mathrm{-5}-3$ and $5-\left(\mathrm{-3}\right).$

Model the first number. | ||

We now add the needed neutral pairs. | ||

We remove the number of counters modeled by the second number. | ||

Count what is left. | ||

### Example 1.15

Subtract: ⓐ $3-1$ ⓑ $\mathrm{-3}-\left(\mathrm{-1}\right)$ ⓒ $\mathrm{-3}-1$ ⓓ $3-\left(\mathrm{-1}\right).$

#### Solution

ⓐ

$\phantom{\rule{0.3em}{0ex}}$ | ||

Take 1 negative from 3 negatives and get 2 negatives positives. |

ⓑ

Take 1 positive from 3 negatives and get 2 negatives. |

ⓒ

$\phantom{\rule{1.8em}{0ex}}$ | ||

Take 1 positive from the one added neutral pair. |

ⓓ

$\phantom{\rule{1.5em}{0ex}}$ | ||

Take 1 negative from the one added neutral pair. |

### Try It 1.29

Subtract: ⓐ $6-4$ ⓑ $\mathrm{-6}-(\mathrm{-4})$ ⓒ $\mathrm{-6}-4$ ⓓ $6-\left(\mathrm{-4}\right).$

### Try It 1.30

Subtract: ⓐ $7-4$ ⓑ $\mathrm{-7}-(\mathrm{-4})$ ⓒ $\mathrm{-7}-4$ ⓓ $7-\left(\mathrm{-4}\right).$

Have you noticed that *subtraction of signed numbers can be done by adding the opposite*? In the last example, $\mathrm{-3}-1$ is the same as $\mathrm{-3}+\left(\mathrm{-1}\right)$ and $3-\left(\mathrm{-1}\right)$ is the same as $3+1.$ You will often see this idea, the Subtraction Property, written as follows:

### Subtraction Property

Subtracting a number is the same as adding its opposite.

### Example 1.16

Simplify: ⓐ $13-8$ and $13+(\mathrm{-8})$ ⓑ $\mathrm{-17}-9$ and $\mathrm{-17}+(\mathrm{-9})$ ⓒ $9-(\mathrm{-15})$ and $9+15$ ⓓ $\mathrm{-7}-(\mathrm{-4})$ and $\mathrm{-7}+4.$

#### Solution

ⓐ

Subtract. | $\begin{array}{ccc}\hfill 13-8\hfill & \hfill \phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}\hfill & \hfill 13+\left(\mathrm{-8}\right)\hfill \\ \hfill 5\hfill & & \hfill 5\hfill \end{array}$ |

ⓑ

Subtract. | $\begin{array}{ccc}\hfill \mathrm{-17}-9\hfill & \hfill \phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}\hfill & \hfill \mathrm{-17}+(\mathrm{-9})\hfill \\ \hfill \mathrm{-26}\hfill & & \hfill \mathrm{-26}\hfill \end{array}$ |

ⓒ

Subtract. | $\begin{array}{ccc}\hfill 9-\left(\mathrm{-15}\right)\hfill & \hfill \phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}\hfill & \hfill 9+15\hfill \\ \hfill 24\hfill & & \hfill 24\hfill \end{array}$ |

ⓓ

Subtract. | $\begin{array}{ccc}\hfill \mathrm{-7}-\left(\mathrm{-4}\right)\hfill & \hfill \phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}\hfill & \hfill \mathrm{-7}+4\hfill \\ \hfill \mathrm{-3}\hfill & & \hfill \mathrm{-3}\hfill \end{array}$ |

### Try It 1.31

Simplify: ⓐ $21-13$ and $21+\left(\mathrm{-13}\right)$ ⓑ $\mathrm{-11}-7$ and $\mathrm{-11}+(\mathrm{-7})$ ⓒ $6-\left(\mathrm{-13}\right)$ and $6+13$ ⓓ $\mathrm{-5}-\left(\mathrm{-1}\right)$ and $\mathrm{-5}+1.$

### Try It 1.32

Simplify: ⓐ $15-7$ and $15+\left(\mathrm{-7}\right)$ ⓑ $\mathrm{-14}-8$ and $\mathrm{-14}+(\mathrm{-8})$ ⓒ $4-\left(\mathrm{-19}\right)$ and $4+19$ ⓓ $\mathrm{-4}-\left(\mathrm{-7}\right)$ and $\mathrm{-4}+7.$

What happens when there are more than three integers? We just use the order of operations as usual.

### Example 1.17

Simplify: $7-\left(\mathrm{-4}-3\right)-9.$

#### Solution

$7-\left(\mathrm{-4}-3\right)-9$ | |

Simplify inside the parentheses first. | $7-\left(\mathrm{-7}\right)-9$ |

Subtract left to right. | $14-9$ |

Subtract. | $5$ |

### Try It 1.33

Simplify: $8-\left(\mathrm{-3}-1\right)-9.$

### Try It 1.34

Simplify: $12-\left(\mathrm{-9}-6\right)-14.$

### Multiply and Divide Integers

Since multiplication is mathematical shorthand for repeated addition, our model can easily be applied to show multiplication of integers. Let’s look at this concrete model to see what patterns we notice. We will use the same examples that we used for addition and subtraction. Here, we are using the model just to help us discover the pattern.

We remember that $a\xb7b$ means **add** *a*, *b* **times**.

The next two examples are more interesting. What does it mean to multiply 5 by $\mathrm{-3}?$ It means subtract $5,3$ times. Looking at subtraction as “taking away”, it means to take away 5, 3 times. But there is nothing to take away, so we start by adding neutral pairs on the workspace.

In summary:

Notice that for multiplication of two signed numbers, when the

What about division? Division is the inverse operation of multiplication. So, $15\xf73=5$ because $5\xb73=15.$ In words, this expression says that 15 can be divided into 3 groups of 5 each because adding five three times gives 15. If you look at some examples of multiplying integers, you might figure out the rules for dividing integers.

Division follows the same rules as multiplication with regard to signs.

### Multiplication and Division of Signed Numbers

For multiplication and division of two signed numbers:

Same signs | Result |
---|---|

• Two positives | Positive |

• Two negatives | Positive |

If the signs are the same, the result is positive.

Different signs | Result |
---|---|

• Positive and negative | Negative |

• Negative and positive | Negative |

If the signs are different, the result is negative.

### Example 1.18

Multiply or divide: ⓐ $\mathrm{-100}\xf7\left(\mathrm{-4}\right)$ ⓑ $7\xb76$ ⓒ $4\left(\mathrm{-8}\right)$ ⓓ $\mathrm{-27}\xf73.$

#### Solution

ⓐ

$\mathrm{-100}\xf7\left(\mathrm{-4}\right)$ | |

Divide, with signs that are the same the quotient is positive. | $25$ |

ⓑ

$7\xb76$ | |

Multiply, with same signs. | $42$ |

ⓒ

$4\left(\mathrm{-8}\right)$ | |

Multiply, with different signs. | $\mathrm{-32}$ |

ⓓ

$\mathrm{-27}\xf73$ | |

Divide, with different signs, the quotient is negative. | $\mathrm{-9}$ |

### Try It 1.35

Multiply or divide: ⓐ $\mathrm{-115}\xf7\left(\mathrm{-5}\right)$ ⓑ $5\xb712$ ⓒ $9\left(\mathrm{-7}\right)$ ⓓ $\mathrm{-63}\xf77.$

### Try It 1.36

Multiply or divide: ⓐ $\mathrm{-117}\xf7\left(\mathrm{-3}\right)$ ⓑ $3\xb713$ ⓒ $7\left(\mathrm{-4}\right)$ ⓓ $\mathrm{-42}\xf76.$

When we multiply a number by 1, the result is the same number. Each time we multiply a number by $\mathrm{-1},$ we get its opposite!

### Multiplication by $\mathrm{-1}$

Multiplying a number by $\mathrm{-1}$ gives its opposite.

### Simplify Expressions with Integers

What happens when there are more than two numbers in an expression? The order of operations still applies when negatives are included. Remember Please Excuse My Dear Aunt Sally?

Let’s try some examples. We’ll simplify expressions that use all four operations with integers—addition, subtraction, multiplication, and division. Remember to follow the order of operations.

### Example 1.19

Simplify: ⓐ ${\left(\mathrm{-2}\right)}^{4}$ ⓑ $\text{\u2212}{2}^{4}.$

#### Solution

Notice the difference in parts (a) and (b). In part (a), the exponent means to raise what is in the parentheses, the $\mathrm{-2}$ to the 4^{th} power. In part (b), the exponent means to raise just the 2 to the 4^{th} power and then take the opposite.

ⓐ

${\left(\mathrm{-2}\right)}^{4}$ | |

Write in expanded form. | $\left(\mathrm{-2}\right)\left(\mathrm{-2}\right)\left(\mathrm{-2}\right)\left(\mathrm{-2}\right)$ |

Multiply. | $4\left(\mathrm{-2}\right)\left(\mathrm{-2}\right)$ |

Multiply. | $\mathrm{-8}\left(\mathrm{-2}\right)$ |

Multiply. | $16$ |

ⓑ

$-{2}^{4}$ | |

Write in expanded form. | $-\left(2\xb72\xb72\xb72\right)$ |

We are asked to find the opposite of ${2}^{4}$. | |

Multiply. | $-\left(4\xb72\xb72\right)$ |

Multiply. | $-\left(8\xb72\right)$ |

Multiply. | $\mathrm{-16}$ |

### Try It 1.37

Simplify: ⓐ ${\left(\mathrm{-3}\right)}^{4}$ ⓑ $\text{\u2212}{3}^{4}.$

### Try It 1.38

Simplify: ⓐ ${\left(\mathrm{-7}\right)}^{2}$ ⓑ $\text{\u2212}{7}^{2}.$

The last example showed us the difference between ${\left(\mathrm{-2}\right)}^{4}$ and $\text{\u2212}{2}^{4}.$ This distinction is important to prevent future errors. The next example reminds us to multiply and divide in order left to right.

### Example 1.20

Simplify: ⓐ $8\left(\mathrm{-9}\right)\xf7{\left(\mathrm{-2}\right)}^{3}$ ⓑ $\mathrm{-30}\xf72+\left(\mathrm{-3}\right)\left(\mathrm{-7}\right).$

#### Solution

ⓐ

$8\left(\mathrm{-9}\right)\xf7{\left(\mathrm{-2}\right)}^{3}$ | |

Exponents first. | $8\left(\mathrm{-9}\right)\xf7\left(\mathrm{-8}\right)$ |

Multiply. | $\mathrm{-72}\xf7\left(\mathrm{-8}\right)$ |

Divide. | $9$ |

ⓑ

$\mathrm{-30}\xf72+\left(\mathrm{-3}\right)\left(\mathrm{-7}\right)$ | |

Multiply and divide left to right, so divide first. | $\mathrm{-15}+\left(\mathrm{-3}\right)\left(\mathrm{-7}\right)$ |

Multiply. | $\mathrm{-15}+21$ |

Add. | $6$ |

### Try It 1.39

Simplify: ⓐ $12\left(\mathrm{-9}\right)\xf7{\left(\mathrm{-3}\right)}^{3}$ ⓑ $\mathrm{-27}\xf73+\left(\mathrm{-5}\right)\left(\mathrm{-6}\right).$

### Try It 1.40

Simplify: ⓐ $18\left(\mathrm{-4}\right)\xf7{\left(\mathrm{-2}\right)}^{3}$ ⓑ $\mathrm{-32}\xf74+\left(\mathrm{-2}\right)\left(\mathrm{-7}\right).$

### Evaluate Variable Expressions with Integers

Remember that to evaluate an expression means to substitute a number for the variable in the expression. Now we can use negative numbers as well as positive numbers.

### Example 1.21

Evaluate $4{x}^{2}-2xy+3{y}^{2}$ when $x=2,y=\mathrm{-1}.$

#### Solution

$\phantom{\rule{4em}{0ex}}$ | ||

Simplify exponents. | ||

Multiply. | ||

Subtract. | ||

Add. |

### Try It 1.41

Evaluate: $3{x}^{2}-2xy+6{y}^{2}$ when $x=1,y=\mathrm{-2}.$

### Try It 1.42

Evaluate: $4{x}^{2}-xy+5{y}^{2}$ when $x=\mathrm{-2},y=3.$

### Translate Phrases to Expressions with Integers

Our earlier work translating English to algebra also applies to phrases that include both positive and negative numbers.

### Example 1.22

Translate and simplify: the sum of 8 and $\mathrm{-12},$ increased by $3.$

#### Solution

$\text{the}\phantom{\rule{0.2em}{0ex}}\mathbf{\text{sum}}\phantom{\rule{0.2em}{0ex}}\underset{\text{\u2013}}{\text{of}}\phantom{\rule{0.2em}{0ex}}8\phantom{\rule{0.2em}{0ex}}\underset{\text{\u2013\u2013\u2013}}{\text{and}}\phantom{\rule{0.2em}{0ex}}\mathrm{-12}\phantom{\rule{0.2em}{0ex}}\text{increased by 3}$ | |

Translate. | $\left[8+\left(\mathrm{-12}\right)\right]+3$ |

Simplify. Be careful not to confuse the brackets with an absolute value sign. | $\left(\mathrm{-4}\right)+3$ |

Add. | $\mathrm{-1}$ |

### Try It 1.43

Translate and simplify the sum of 9 and $\mathrm{-16},$ increased by 4.

### Try It 1.44

Translate and simplify the sum of $\mathrm{-8}$ and $\mathrm{-12},$ increased by 7.

### Use Integers in Applications

We’ll outline a plan to solve applications. It’s hard to find something if we don’t know what we’re looking for or what to call it! So when we solve an application, we first need to determine what the problem is asking us to find. Then we’ll write a phrase that gives the information to find it. We’ll translate the phrase into an expression and then simplify the expression to get the answer. Finally, we summarize the answer in a sentence to make sure it makes sense.

### Example 1.23

#### How to Solve Application Problems Using Integers

In the morning, the temperature in Kendallville, Indiana was 11 degrees. By mid-afternoon, the temperature had dropped to $\mathrm{-9}$ degrees. What was the difference in the morning and afternoon temperatures?

#### Solution

### Try It 1.45

In the morning, the temperature in Anchorage, Alaska was $15$ degrees. By mid-afternoon the temperature had dropped to 30 degrees below zero. What was the difference in the morning and afternoon temperatures?

### Try It 1.46

The temperature in Denver was $\mathrm{-6}$ degrees at lunchtime. By sunset the temperature had dropped to $\mathrm{-15}$ degrees. What was the difference in the lunchtime and sunset temperatures?

### How To

#### Use Integers in Applications.

- Step 1.
**Read**the problem. Make sure all the words and ideas are understood. - Step 2.
**Identify**what we are asked to find. - Step 3.
**Write a phrase**that gives the information to find it. - Step 4.
**Translate**the phrase to an expression. - Step 5.
**Simplify**the expression. - Step 6.
**Answer**the question with a complete sentence.

### Media

Access this online resource for additional instruction and practice with integers.

### Section 1.2 Exercises

#### Practice Makes Perfect

**Simplify Expressions with Absolute Value**

In the following exercises, fill in $<,>,$ or $=$ for each of the following pairs of numbers.

ⓐ $\left|\mathrm{-7}\right|\_\_\_-\left|\mathrm{-7}\right|$

ⓑ $6\_\_\_-\left|\mathrm{-6}\right|$

ⓒ $\left|\mathrm{-11}\right|\_\_\_-11$

ⓓ $\text{\u2212}\left(\mathrm{-13}\right)\_\_\_-\left|\mathrm{-13}\right|$

ⓐ $\text{\u2212}\left|\mathrm{-9}\right|\_\_\_\left|\mathrm{-9}\right|$

ⓑ $\mathrm{-8}\_\_\_\left|\mathrm{-8}\right|$

ⓒ $\left|\mathrm{-1}\right|\_\_\_-1$

ⓓ $\text{\u2212}\left(\mathrm{-14}\right)\_\_\_-\left|\mathrm{-14}\right|$

ⓐ $\text{\u2212}\left|2\right|\_\_\_-\left|\mathrm{-2}\right|$

ⓑ $\mathrm{-12}\_\_\_-\left|\mathrm{-12}\right|$

ⓒ $\left|\mathrm{-3}\right|\_\_\_-3$

ⓓ $\left|\mathrm{-19}\right|\_\_\_-\left(\mathrm{-19}\right)$

ⓐ $\text{\u2212}\left|\mathrm{-4}\right|\_\_\_-\left|4\right|$

ⓑ $5\_\_\_-\left|\mathrm{-5}\right|$

ⓒ $\text{\u2212}\left|\mathrm{-10}\right|\_\_\_-10$

ⓓ $\text{\u2212}\left|\mathrm{-0}\right|\_\_\_-\left(\mathrm{-0}\right)$

In the following exercises, simplify.

$\left|17-8\right|-\left|13-4\right|$

$15-\left|3\left(8-5\right)\right|$

$27-\left|19+4\left(3-1\right)-7\right|$

$13-2\left|11-2\left(5-2\right)\right|$

**Add and Subtract Integers**

In the following exercises, simplify each expression.

ⓐ $\mathrm{-5}+\left(\mathrm{-9}\right)$

ⓑ $\mathrm{-5}+9$

ⓒ $5+\left(\mathrm{-9}\right)$

$34+\left(\mathrm{-19}\right)$

$\mathrm{-17}+\left(\mathrm{-18}\right)+6$

$24+3\left(\mathrm{-5}+9\right)$

ⓐ $15-8$

ⓑ $\mathrm{-15}-(\mathrm{-8})$

ⓒ $\mathrm{-15}-8$

ⓓ $15-\left(\mathrm{-8}\right)$

$\mathrm{-58}-\left(\mathrm{-67}\right)$

$64+\left(\mathrm{-17}\right)-9$

ⓐ $35-16$ ⓑ $35+\left(\mathrm{-16}\right)$

ⓐ $46-\left(\mathrm{-37}\right)$ ⓑ $46+37$

$\left(1-8\right)-\left(2-9\right)$

$\text{\u2212}\left(4-5\right)-\left(7-8\right)$

$32-\left[5-\left(15-20\right)\right]$

**Multiply and Divide Integers**

In the following exercises, multiply or divide.

ⓐ $\mathrm{-4}\xb78$

ⓑ $13\left(\mathrm{-5}\right)$

ⓒ $\mathrm{-24}\xf76$

ⓓ $\mathrm{-52}\xf7\left(\mathrm{-4}\right)$

ⓐ $\mathrm{-3}\xb79$

ⓑ $9\left(\mathrm{-7}\right)$

ⓒ $35\xf7\left(\mathrm{-7}\right)$

ⓓ $\mathrm{-84}\xf7\left(\mathrm{-6}\right)$

ⓐ $\mathrm{-28}\xf77$

ⓑ $\mathrm{-180}\xf715$

ⓒ $3\left(\mathrm{-13}\right)$

ⓓ $\mathrm{-1}\left(\mathrm{-14}\right)$

ⓐ $\mathrm{-36}\xf74$

ⓑ $\mathrm{-192}\xf712$

ⓒ $9\left(\mathrm{-7}\right)$

ⓓ $\mathrm{-1}\left(\mathrm{-19}\right)$

**Simplify and Evaluate Expressions with Integers**

In the following exercises, simplify each expression.

ⓐ ${\left(\mathrm{-3}\right)}^{5}$ ⓑ $\text{\u2212}{3}^{5}$

$8\left(\mathrm{-4}\right)+5\left(\mathrm{-4}\right)-6$

$\mathrm{-4}\left(\mathrm{-6}\right)\left(3\right)$

$\left(6-11\right)\left(8-13\right)$

$23-2\left(4-6\right)$

$52\xf7\left(\mathrm{-4}\right)+\left(\mathrm{-32}\right)\xf7\left(\mathrm{-8}\right)$

$11-3\left[7-4\left(\mathrm{-2}\right)\right]$

$7-\left|5-3\left(4-1\right)-6\right|$

$5-2\left|2\left(1-4\right)-\left(2-5\right)\right|$

${\left(\mathrm{-4}\right)}^{2}-32\xf7\left(12-4\right)$

In the following exercises, evaluate each expression.

$x+\left(\mathrm{-21}\right)$ when

ⓐ $x=\mathrm{-27}$
ⓑ $x=44$

${\left(y+z\right)}^{2}$ when

$y=\mathrm{-3},z=15$

$7m-4n-2$ when

$m=\mathrm{-4}$ and $n=\mathrm{-9}$

$4{x}^{2}-xy+3{y}^{2}$ when

$x=\mathrm{-3},y=\mathrm{-2}$

**Translate English Phrases to Algebraic Expressions**

In the following exercises, translate to an algebraic expression and simplify if possible.

the sum of $\mathrm{-8}$ and $\mathrm{-9},$ increased by $23$

ⓐ the difference of $\mathrm{-5}$ and $\mathrm{-30}$

ⓑ subtract $\mathrm{-6}$ from $\mathrm{-13}$

the product of $\mathrm{-13}$ and the difference of $c$ and $d$

**Use Integers in Applications**

In the following exercises, solve.

**Temperature** On January 15, the high temperature in Anaheim, California, was 84°. That same day, the high temperature in Embarrass, Minnesota, was $\text{\u2212}12\text{\xb0}.$ What was the difference between the temperature in Anaheim and the temperature in Embarrass?

**Temperature** On January 21, the high temperature in Palm Springs, California, was $89\text{\xb0},$ and the high temperature in Whitefield, New Hampshire, was $\text{\u2212}31\text{\xb0}.$ What was the difference between the temperature in Palm Springs and the temperature in Whitefield?

**Football** On the first down, the Chargers had the ball on their 25-yard line. They lost 6 yards on the first-down play, gained 10 yards on the second-down play, and lost 8 yards on the third-down play. What was the yard line at the end of the third-down play?

**Football** On first down, the Steelers had the ball on their 30-yard line. They gained 9 yards on the first-down play, lost 14 yards on the second-down play, and lost 2 yards on the third-down play. What was the yard line at the end of the third-down play?

**Checking Account** Mayra has $124 in her checking account. She writes a check for $152. What is the new balance in her checking account?

**Checking Account** Reymonte has a balance of $\text{\u2212}\text{\$}49$ in his checking account. He deposits $281 to the account. What is the new balance?

#### Writing Exercises

Explain why the sum of $\mathrm{-8}$ and 2 is negative, but the sum of 8 and $\mathrm{-2}$ is positive.

Give an example from your life experience of adding two negative numbers.

Why is $\text{\u2212}{4}^{3}={\left(\mathrm{-4}\right)}^{3}?$

#### Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ After reviewing this checklist, what will you do to become confident for all objectives?