We know that visible light is the type of electromagnetic wave to which our eyes respond. Like all other electromagnetic waves, it obeys the equation

where $c=3\times {\text{10}}^{8}\phantom{\rule{0.25em}{0ex}}\text{m/s}$ is the speed of light in vacuum, $f$ is the frequency of the electromagnetic waves, and $\lambda $ is its wavelength. The range of visible wavelengths is approximately 380 to 760 nm. As is true for all waves, light travels in straight lines and acts like a ray when it interacts with objects several times as large as its wavelength. However, when it interacts with smaller objects, it displays its wave characteristics prominently. Interference is the hallmark of a wave, and in Figure 27.3 both the ray and wave characteristics of light can be seen. The laser beam emitted by the observatory epitomizes a ray, traveling in a straight line. However, passing a pure-wavelength beam through vertical slits with a size close to the wavelength of the beam reveals the wave character of light, as the beam spreads out horizontally into a pattern of bright and dark regions caused by systematic constructive and destructive interference. Rather than spreading out, a ray would continue traveling straight ahead after passing through slits.

### Making Connections: Waves

The most certain indication of a wave is interference. This wave characteristic is most prominent when the wave interacts with an object that is not large compared with the wavelength. Interference is observed for water waves, sound waves, light waves, and (as we will see in Special Relativity) for matter waves, such as electrons scattered from a crystal.

Light has wave characteristics in various media as well as in a vacuum. When light goes from a vacuum to some medium, like water, its speed and wavelength change, but its frequency $f$ remains the same. (We can think of light as a forced oscillation that must have the frequency of the original source.) The speed of light in a medium is $v=c/n$, where $n$ is its index of refraction. If we divide both sides of equation $c=f\lambda $ by $n$, we get $c/n=v=f\lambda /n$. This implies that $v=f{\lambda}_{\text{n}}$, where ${\lambda}_{\text{n}}$ is the wavelength in a medium and that

where $\lambda $ is the wavelength in vacuum and $n$ is the medium’s index of refraction. Therefore, the wavelength of light is smaller in any medium than it is in vacuum. In water, for example, which has $n=1\text{.}\text{333}$, the range of visible wavelengths is $(\text{380}\phantom{\rule{0.25em}{0ex}}\text{nm})\text{/1}\text{.}\text{333}$ to $(\text{760}\phantom{\rule{0.25em}{0ex}}\text{nm})\text{/1}\text{.}\text{333}$, or ${\lambda}_{\text{n}}=\text{285}\phantom{\rule{0.25em}{0ex}}\text{to}\phantom{\rule{0.25em}{0ex}}\text{570}\phantom{\rule{0.25em}{0ex}}\text{nm}$. Although wavelengths change while traveling from one medium to another, colors do not, since colors are associated with frequency.