College Physics for AP® Courses

# 25.3The Law of Refraction

College Physics for AP® Courses25.3 The Law of Refraction

### Learning Objectives

By the end of this section, you will be able to:

• Determine the index of refraction, given the speed of light in a medium.

The information presented in this section supports the following AP® learning objectives and science practices:

• 6.E.1.1 The student is able to make claims using connections across concepts about the behavior of light as the wave travels from one medium into another, as some is transmitted, some is reflected, and some is absorbed. (S.P. 6.4, 7.2)
• 6.E.3.1 The student is able to describe models of light traveling across a boundary from one transparent material to another when the speed of propagation changes, causing a change in the path of the light ray at the boundary of the two media. (S.P. 1.1, 1.4)
• 6.E.3.2 The student is able to plan data collection strategies as well as perform data analysis and evaluation of the evidence for finding the relationship between the angle of incidence and the angle of refraction for light crossing boundaries from one transparent material to another (Snell’s law). (S.P. 4.1, 5.1, 5.2, 5.3)
• 6.E.3.3 The student is able to make claims and predictions about path changes for light traveling across a boundary from one transparent material to another at non-normal angles resulting from changes in the speed of propagation. (S.P. 6.4, 7.2)

It is easy to notice some odd things when looking into a fish tank. For example, you may see the same fish appearing to be in two different places. (See Figure 25.9.) This is because light coming from the fish to us changes direction when it leaves the tank, and in this case, it can travel two different paths to get to our eyes. The changing of a light ray’s direction (loosely called bending) when it passes through variations in matter is called refraction. Refraction is responsible for a tremendous range of optical phenomena, from the action of lenses to voice transmission through optical fibers.

### Refraction

The changing of a light ray’s direction (loosely called bending) when it passes through variations in matter is called refraction.

### Speed of Light

The speed of light $cc size 12{c} {}$ not only affects refraction, it is one of the central concepts of Einstein’s theory of relativity. As the accuracy of the measurements of the speed of light were improved, $cc size 12{c} {}$ was found not to depend on the velocity of the source or the observer. However, the speed of light does vary in a precise manner with the material it traverses. These facts have far-reaching implications, as we will see in Special Relativity. It makes connections between space and time and alters our expectations that all observers measure the same time for the same event, for example. The speed of light is so important that its value in a vacuum is one of the most fundamental constants in nature as well as being one of the four fundamental SI units.

Figure 25.9 Looking at the fish tank as shown, we can see the same fish in two different locations, because light changes directions when it passes from water to air. In this case, the light can reach the observer by two different paths, and so the fish seems to be in two different places. This bending of light is called refraction and is responsible for many optical phenomena.

Why does light change direction when passing from one material (medium) to another? It is because light changes speed when going from one material to another. So before we study the law of refraction, it is useful to discuss the speed of light and how it varies in different media.

### The Speed of Light

Early attempts to measure the speed of light, such as those made by Galileo, determined that light moved extremely fast, perhaps instantaneously. The first real evidence that light traveled at a finite speed came from the Danish astronomer Ole Roemer in the late 17th century. Roemer had noted that the average orbital period of one of Jupiter’s moons, as measured from Earth, varied depending on whether Earth was moving toward or away from Jupiter. He correctly concluded that the apparent change in period was due to the change in distance between Earth and Jupiter and the time it took light to travel this distance. From his 1676 data, a value of the speed of light was calculated to be $2.26×108 m/s2.26×108 m/s size 12{2 "." "26"´"10" rSup { size 8{8} } " m/s"} {}$ (only 25% different from today’s accepted value). In more recent times, physicists have measured the speed of light in numerous ways and with increasing accuracy. One particularly direct method, used in 1887 by the American physicist Albert Michelson (1852–1931), is illustrated in Figure 25.10. Light reflected from a rotating set of mirrors was reflected from a stationary mirror 35 km away and returned to the rotating mirrors. The time for the light to travel can be determined by how fast the mirrors must rotate for the light to be returned to the observer’s eye.

Figure 25.10 A schematic of early apparatus used by Michelson and others to determine the speed of light. As the mirrors rotate, the reflected ray is only briefly directed at the stationary mirror. The returning ray will be reflected into the observer's eye only if the next mirror has rotated into the correct position just as the ray returns. By measuring the correct rotation rate, the time for the round trip can be measured and the speed of light calculated. Michelson’s calculated value of the speed of light was only 0.04% different from the value used today.

The speed of light is now known to great precision. In fact, the speed of light in a vacuum $cc size 12{c} {}$ is so important that it is accepted as one of the basic physical quantities and has the fixed value

$c=2.99792458×108 m/s≈3.00×108 m/s,c=2.99792458×108 m/s≈3.00×108 m/s, size 12{c=2 "." "99792458" times "10" rSup { size 8{8} } " m/s" approx 3 "." "00" times "10" rSup { size 8{8} } " m/s"} {}$
25.1

where the approximate value of $3.00×108 m/s3.00×108 m/s size 12{3 "." "00"´"10" rSup { size 8{8} } " m/s"} {}$ is used whenever three-digit accuracy is sufficient. The speed of light through matter is less than it is in a vacuum, because light interacts with atoms in a material. The speed of light depends strongly on the type of material, since its interaction with different atoms, crystal lattices, and other substructures varies. We define the index of refraction $nn size 12{n} {}$ of a material to be

$n=cv,n=cv, size 12{n= { {c} over {v} } } {}$
25.2

where $vv size 12{v} {}$ is the observed speed of light in the material. Since the speed of light is always less than $cc size 12{c} {}$ in matter and equals $cc size 12{c} {}$ only in a vacuum, the index of refraction is always greater than or equal to one.

### Value of the Speed of Light

$c=2.99792458×108 m/s≈3.00×108 m/sc=2.99792458×108 m/s≈3.00×108 m/s$
25.3

### Index of Refraction

$n=cvn=cv size 12{n= { {c} over {v} } } {}$
25.4

That is, $n≥1n≥1 size 12{n >= 1} {}$. Table 25.1 gives the indices of refraction for some representative substances. The values are listed for a particular wavelength of light, because they vary slightly with wavelength. (This can have important effects, such as colors produced by a prism.) Note that for gases, $nn size 12{n} {}$ is close to 1.0. This seems reasonable, since atoms in gases are widely separated and light travels at $cc size 12{c} {}$ in the vacuum between atoms. It is common to take $n=1n=1 size 12{n=1} {}$ for gases unless great precision is needed. Although the speed of light $vv size 12{v} {}$ in a medium varies considerably from its value $cc size 12{c} {}$ in a vacuum, it is still a large speed.

Medium n
Gases at $0ºC0ºC$, 1 atm
Air 1.000293
Carbon dioxide 1.00045
Hydrogen 1.000139
Oxygen 1.000271
Liquids at $20ºC20ºC$
Benzene 1.501
Carbon disulfide 1.628
Carbon tetrachloride 1.461
Ethanol 1.361
Glycerine 1.473
Water, fresh 1.333
Solids at $20ºC20ºC$
Diamond 2.419
Fluorite 1.434
Glass, crown 1.52
Glass, flint 1.66
Ice at $20ºC20ºC$ 1.309
Polystyrene 1.49
Plexiglas 1.51
Quartz, crystalline 1.544
Quartz, fused 1.458
Sodium chloride 1.544
Zircon 1.923
Table 25.1 Index of Refraction in Various Media

### Example 25.1Speed of Light in Matter

Calculate the speed of light in zircon, a material used in jewelry to imitate diamond.

Strategy

The speed of light in a material, $vv size 12{v} {}$, can be calculated from the index of refraction $nn size 12{n} {}$ of the material using the equation $n=c/vn=c/v size 12{n=c/2} {}$.

Solution

The equation for index of refraction states that $n=c/vn=c/v size 12{n=c/v} {}$. Rearranging this to determine $vv size 12{v} {}$ gives

$v=cn.v=cn. size 12{v= { {c} over {n} } } {}$
25.5

The index of refraction for zircon is given as 1.923 in Table 25.1, and $cc size 12{c} {}$ is given in the equation for speed of light. Entering these values in the last expression gives

v = 3.00×108 m/s1.923 = 1.56×108 m/s. v = 3.00×108 m/s1.923 = 1.56×108 m/s. alignl { stack { size 12{v= { {3 "." "00"´"10" rSup { size 8{8} } " m/s"} over {1 "." "923"} } } {} # =1 "." "56"´"10" rSup { size 8{8} } " m/s" "." {} } } {}
25.6

Discussion

This speed is slightly larger than half the speed of light in a vacuum and is still high compared with speeds we normally experience. The only substance listed in Table 25.1 that has a greater index of refraction than zircon is diamond. We shall see later that the large index of refraction for zircon makes it sparkle more than glass, but less than diamond.

### Law of Refraction

Figure 25.11 shows how a ray of light changes direction when it passes from one medium to another. As before, the angles are measured relative to a perpendicular to the surface at the point where the light ray crosses it. (Some of the incident light will be reflected from the surface, but for now we will concentrate on the light that is transmitted.) The change in direction of the light ray depends on how the speed of light changes. The change in the speed of light is related to the indices of refraction of the media involved. In the situations shown in Figure 25.11, medium 2 has a greater index of refraction than medium 1. This means that the speed of light is less in medium 2 than in medium 1. Note that as shown in Figure 25.11(a), the direction of the ray moves closer to the perpendicular when it slows down. Conversely, as shown in Figure 25.11(b), the direction of the ray moves away from the perpendicular when it speeds up. The path is exactly reversible. In both cases, you can imagine what happens by thinking about pushing a lawn mower from a footpath onto grass, and vice versa. Going from the footpath to grass, the front wheels are slowed and pulled to the side as shown. This is the same change in direction as for light when it goes from a fast medium to a slow one. When going from the grass to the footpath, the front wheels can move faster and the mower changes direction as shown. This, too, is the same change in direction as for light going from slow to fast.

Figure 25.11 The change in direction of a light ray depends on how the speed of light changes when it crosses from one medium to another. The speed of light is greater in medium 1 than in medium 2 in the situations shown here. (a) A ray of light moves closer to the perpendicular when it slows down. This is analogous to what happens when a lawn mower goes from a footpath to grass. (b) A ray of light moves away from the perpendicular when it speeds up. This is analogous to what happens when a lawn mower goes from grass to footpath. The paths are exactly reversible.

The amount that a light ray changes its direction depends both on the incident angle and the amount that the speed changes. For a ray at a given incident angle, a large change in speed causes a large change in direction, and thus a large change in angle. The exact mathematical relationship is the law of refraction, or “Snell’s Law,” which is stated in equation form as

$n1sinθ1=n2sinθ2.n1sinθ1=n2sinθ2. size 12{n rSub { size 8{1} } "sin"θ rSub { size 8{1} } =n rSub { size 8{2} } "sin"θ rSub { size 8{2} } } {}$
25.7

Here $n1n1 size 12{n rSub { size 8{1} } } {}$ and $n2n2 size 12{n rSub { size 8{2} } } {}$ are the indices of refraction for medium 1 and 2, and $θ1θ1 size 12{q rSub { size 8{1} } } {}$ and $θ2θ2 size 12{q rSub { size 8{2} } } {}$ are the angles between the rays and the perpendicular in medium 1 and 2, as shown in Figure 25.11. The incoming ray is called the incident ray and the outgoing ray the refracted ray, and the associated angles the incident angle and the refracted angle. The law of refraction is also called Snell’s law after the Dutch mathematician Willebrord Snell (1591–1626), who discovered it in 1621. Snell’s experiments showed that the law of refraction was obeyed and that a characteristic index of refraction $nn size 12{n} {}$ could be assigned to a given medium. Snell was not aware that the speed of light varied in different media, but through experiments he was able to determine indices of refraction from the way light rays changed direction.

### The Law of Refraction

$n1sinθ1=n2sinθ2n1sinθ1=n2sinθ2 size 12{n rSub { size 8{1} } "sin"θ rSub { size 8{1} } =n rSub { size 8{2} } "sin"θ rSub { size 8{2} } } {}$
25.8

### Take-Home Experiment: A Broken Pencil

A classic observation of refraction occurs when a pencil is placed in a glass half filled with water. Do this and observe the shape of the pencil when you look at the pencil sideways, that is, through air, glass, water. Explain your observations. Draw ray diagrams for the situation.

### Example 25.2Determine the Index of Refraction from Refraction Data

Find the index of refraction for medium 2 in Figure 25.11(a), assuming medium 1 is air and given the incident angle is $30.0º30.0º size 12{"30" "." 0°} {}$ and the angle of refraction is $22.0º22.0º size 12{"22" "." 0°} {}$.

Strategy

The index of refraction for air is taken to be 1 in most cases (and up to four significant figures, it is 1.000). Thus $n1=1.00n1=1.00 size 12{n rSub { size 8{1} } =1 "." "00"} {}$ here. From the given information, $θ1=30.0ºθ1=30.0º size 12{q rSub { size 8{1} } ="30" "." 0°} {}$ and $θ2=22.0ºθ2=22.0º size 12{q rSub { size 8{2} } ="22" "." 0°} {}$. With this information, the only unknown in Snell’s law is $n2n2 size 12{n rSub { size 8{2} } } {}$, so that it can be used to find this unknown.

Solution

Snell’s law is

$n1sinθ1=n2sinθ2.n1sinθ1=n2sinθ2. size 12{n rSub { size 8{1} } "sin"θ rSub { size 8{1} } =n rSub { size 8{2} } "sin"θ rSub { size 8{2} } } {}$
25.9

Rearranging to isolate $n2n2 size 12{n rSub { size 8{2} } } {}$ gives

$n2=n1sinθ1sinθ2.n2=n1sinθ1sinθ2. size 12{n rSub { size 8{2} } =n rSub { size 8{1} } { {"sin"θ rSub { size 8{1} } } over {"sin"θ rSub { size 8{2} } } } } {}$
25.10

Entering known values,

n2=1.00sin30.0ºsin22.0º=0.5000.375 =1.33.n2=1.00sin30.0ºsin22.0º=0.5000.375 =1.33.alignl { stack { size 12{n rSub { size 8{2} } =1 "." "00" { {"sin""30" "." 0°} over {"sin""22" "." 0°} } = { {0 "." "500"} over {0 "." "375"} } } {} # =1 "." "33" "." {} } } {}
25.11

Discussion

This is the index of refraction for water, and Snell could have determined it by measuring the angles and performing this calculation. He would then have found 1.33 to be the appropriate index of refraction for water in all other situations, such as when a ray passes from water to glass. Today we can verify that the index of refraction is related to the speed of light in a medium by measuring that speed directly.

### Example 25.3A Larger Change in Direction

Suppose that in a situation like that in Example 25.2, light goes from air to diamond and that the incident angle is $30.0º30.0º size 12{"30" "." 0°} {}$. Calculate the angle of refraction $θ2θ2 size 12{q rSub { size 8{2} } } {}$ in the diamond.

Strategy

Again the index of refraction for air is taken to be $n1=1.00n1=1.00 size 12{n rSub { size 8{1} } =1 "." "00"} {}$, and we are given $θ1=30.0ºθ1=30.0º size 12{q rSub { size 8{1} } ="30" "." 0°} {}$. We can look up the index of refraction for diamond in Table 25.1, finding $n2=2.419n2=2.419 size 12{n rSub { size 8{2} } =2 "." "419"} {}$. The only unknown in Snell’s law is $θ2θ2 size 12{q rSub { size 8{2} } } {}$, which we wish to determine.

Solution

Solving Snell’s law for sin $θ2θ2 size 12{q rSub { size 8{2} } } {}$ yields

$sinθ2=n1n2sinθ1.sinθ2=n1n2sinθ1. size 12{"sin"θ rSub { size 8{2} } = { {n rSub { size 8{1} } } over {n rSub { size 8{2} } } } "sin"θ rSub { size 8{1} } } {}$
25.12

Entering known values,

$sinθ2=1.002.419sin30.0º=(0.413)(0.500)=0.207.sinθ2=1.002.419sin30.0º=(0.413)(0.500)=0.207. size 12{"sin"q rSub { size 8{2} } = { {1 "." "00"} over {2 "." "419"} } "sin""30" "." 0"°=" left (0 "." "413" right ) left (0 "." "500" right )=0 "." "207"} {}$
25.13

The angle is thus

$θ2=sin−10.207=11.9º.θ2=sin−10.207=11.9º. size 12{θ rSub { size 8{2} } ="sin" rSup { size 8{ - 1} } 0 "." "207"="11" "." 9°} {}$
25.14

Discussion

For the same $30º30º$ angle of incidence, the angle of refraction in diamond is significantly smaller than in water ($11.9º11.9º$ rather than $22º22º$—see the preceding example). This means there is a larger change in direction in diamond. The cause of a large change in direction is a large change in the index of refraction (or speed). In general, the larger the change in speed, the greater the effect on the direction of the ray.