Skip to ContentGo to accessibility pageKeyboard shortcuts menu
OpenStax Logo
Chemistry: Atoms First

B | Essential Mathematics

Chemistry: Atoms FirstB | Essential Mathematics

Exponential Arithmetic

Exponential notation is used to express very large and very small numbers as a product of two numbers. The first number of the product, the digit term, is usually a number not less than 1 and not greater than 10. The second number of the product, the exponential term, is written as 10 with an exponent. Some examples of exponential notation are:

1000=1×103 100=1×102 10=1×101 1=1×100 0.1=1×10−1 0.001=1×10−3 2386=2.386×1000=2.386×103 0.123=1.23×0.1=1.23×10−11000=1×103 100=1×102 10=1×101 1=1×100 0.1=1×10−1 0.001=1×10−3 2386=2.386×1000=2.386×103 0.123=1.23×0.1=1.23×10−1

The power (exponent) of 10 is equal to the number of places the decimal is shifted to give the digit number. The exponential method is particularly useful notation for every large and very small numbers. For example, 1,230,000,000 = 1.23 ×× 109, and 0.00000000036 = 3.6 ×× 10−10.

Addition of Exponentials

Convert all numbers to the same power of 10, add the digit terms of the numbers, and if appropriate, convert the digit term back to a number between 1 and 10 by adjusting the exponential term.

Example B1

Adding Exponentials

Add 5.00 ×× 10−5 and 3.00 ×× 10−3.

Solution

3.00×10−3=300×10−5(5.00×10−5)+(300×10−5)=305×10−5=3.05×10−33.00×10−3=300×10−5(5.00×10−5)+(300×10−5)=305×10−5=3.05×10−3

Subtraction of Exponentials

Convert all numbers to the same power of 10, take the difference of the digit terms, and if appropriate, convert the digit term back to a number between 1 and 10 by adjusting the exponential term.

Example B2

Subtracting Exponentials

Subtract 4.0 ×× 10−7 from 5.0 ×× 10−6.

Solution

4.0×10−7=0.40×10−6(5.0×10−6)−(0.40×10−6)=4.6×10−64.0×10−7=0.40×10−6(5.0×10−6)−(0.40×10−6)=4.6×10−6

Multiplication of Exponentials

Multiply the digit terms in the usual way and add the exponents of the exponential terms.

Example B3

Multiplying Exponentials

Multiply 4.2 ×× 10−8 by 2.0 ×× 103.

Solution

(4.2×10−8)×(2.0×103)=(4.2×2.0)×10(−8)+(+3)=8.4×10−5(4.2×10−8)×(2.0×103)=(4.2×2.0)×10(−8)+(+3)=8.4×10−5

Division of Exponentials

Divide the digit term of the numerator by the digit term of the denominator and subtract the exponents of the exponential terms.

Example B4

Dividing Exponentials

Divide 3.6 ×× 105 by 6.0 ×× 10−4.

Solution

3.6×10−56.0×10−4=(3.66.0)×10(−5)−(−4)=0.60×10−1=6.0×10−23.6×10−56.0×10−4=(3.66.0)×10(−5)−(−4)=0.60×10−1=6.0×10−2

Squaring of Exponentials

Square the digit term in the usual way and multiply the exponent of the exponential term by 2.

Example B5

Squaring Exponentials

Square the number 4.0 ×× 10−6.

Solution

(4.0×10−6)2=4×4×102×(−6)=16×10−12=1.6×10−11(4.0×10−6)2=4×4×102×(−6)=16×10−12=1.6×10−11

Cubing of Exponentials

Cube the digit term in the usual way and multiply the exponent of the exponential term by 3.

Example B6

Cubing Exponentials

Cube the number 2 ×× 104.

Solution

(2×104)3=2×2×2×103×4=8×1012(2×104)3=2×2×2×103×4=8×1012

Taking Square Roots of Exponentials

If necessary, decrease or increase the exponential term so that the power of 10 is evenly divisible by 2. Extract the square root of the digit term and divide the exponential term by 2.

Example B7

Finding the Square Root of Exponentials

Find the square root of 1.6 ×× 10−7.

Solution

1.6×10−7=16×10−816×10−8=16×10−8=16×10−82=4.0×10−41.6×10−7=16×10−816×10−8=16×10−8=16×10−82=4.0×10−4

Significant Figures

A beekeeper reports that he has 525,341 bees. The last three figures of the number are obviously inaccurate, for during the time the keeper was counting the bees, some of them died and others hatched; this makes it quite difficult to determine the exact number of bees. It would have been more accurate if the beekeeper had reported the number 525,000. In other words, the last three figures are not significant, except to set the position of the decimal point. Their exact values have no meaning useful in this situation. In reporting any information as numbers, use only as many significant figures as the accuracy of the measurement warrants.

The importance of significant figures lies in their application to fundamental computation. In addition and subtraction, the sum or difference should contain as many digits to the right of the decimal as that in the least certain of the numbers used in the computation (indicated by underscoring in the following example).

Example B8

Addition and Subtraction with Significant Figures

Add 4.383 g and 0.0023 g.

Solution

4.383_g0.0023_g4.385_g4.383_g0.0023_g4.385_g

In multiplication and division, the product or quotient should contain no more digits than that in the factor containing the least number of significant figures.

Example B9

Multiplication and Division with Significant Figures

Multiply 0.6238 by 6.6.

Solution

0.6238_×6.6_=4.1_0.6238_×6.6_=4.1_

When rounding numbers, increase the retained digit by 1 if it is followed by a number larger than 5 (“round up”). Do not change the retained digit if the digits that follow are less than 5 (“round down”). If the retained digit is followed by 5, round up if the retained digit is odd, or round down if it is even (after rounding, the retained digit will thus always be even).

The Use of Logarithms and Exponential Numbers

The common logarithm of a number (log) is the power to which 10 must be raised to equal that number. For example, the common logarithm of 100 is 2, because 10 must be raised to the second power to equal 100. Additional examples follow.

Logarithms and Exponential Numbers
Number Number Expressed Exponentially Common Logarithm
1000 103 3
10 101 1
1 100 0
0.1 10−1 −1
0.001 10−3 −3
Table B1

What is the common logarithm of 60? Because 60 lies between 10 and 100, which have logarithms of 1 and 2, respectively, the logarithm of 60 is 1.7782; that is,

60=101.778260=101.7782

The common logarithm of a number less than 1 has a negative value. The logarithm of 0.03918 is −1.4069, or

0.03918=10−1.4069=1101.40690.03918=10−1.4069=1101.4069

To obtain the common logarithm of a number, use the log button on your calculator. To calculate a number from its logarithm, take the inverse log of the logarithm, or calculate 10x (where x is the logarithm of the number).

The natural logarithm of a number (ln) is the power to which e must be raised to equal the number; e is the constant 2.7182818. For example, the natural logarithm of 10 is 2.303; that is,

10=e2.303=2.71828182.30310=e2.303=2.71828182.303

To obtain the natural logarithm of a number, use the ln button on your calculator. To calculate a number from its natural logarithm, enter the natural logarithm and take the inverse ln of the natural logarithm, or calculate ex (where x is the natural logarithm of the number).

Logarithms are exponents; thus, operations involving logarithms follow the same rules as operations involving exponents.

  1. The logarithm of a product of two numbers is the sum of the logarithms of the two numbers.
    logxy=logx+logy,and lnxy=lnx+lnylogxy=logx+logy,and lnxy=lnx+lny
  2. The logarithm of the number resulting from the division of two numbers is the difference between the logarithms of the two numbers.
    logxy=logx−logy,and lnxy=lnx−lnylogxy=logx−logy,and lnxy=lnx−lny
  3. The logarithm of a number raised to an exponent is the product of the exponent and the logarithm of the number.
    logxn=nlogxand lnxn=nlnxlogxn=nlogxand lnxn=nlnx

The Solution of Quadratic Equations

Mathematical functions of this form are known as second-order polynomials or, more commonly, quadratic functions.

ax2+bx+c=0ax2+bx+c=0

The solution or roots for any quadratic equation can be calculated using the following formula:

x=−b±b2−4ac2ax=−b±b2−4ac2a
Example B10

Solving Quadratic Equations

Solve the quadratic equation 3x2 + 13x − 10 = 0.

Solution

Substituting the values a = 3, b = 13, c = −10 in the formula, we obtain
x=−13±(13)2−4×3×(−10)2×3x=−13±(13)2−4×3×(−10)2×3
x=−13±169+1206=−13±2896=−13±176x=−13±169+1206=−13±2896=−13±176

The two roots are therefore

x=−13+176=23andx=−13−176=−5x=−13+176=23andx=−13−176=−5

Quadratic equations constructed on physical data always have real roots, and of these real roots, often only those having positive values are of any significance.

Two-Dimensional (x-y) Graphing

The relationship between any two properties of a system can be represented graphically by a two-dimensional data plot. Such a graph has two axes: a horizontal one corresponding to the independent variable, or the variable whose value is being controlled (x), and a vertical axis corresponding to the dependent variable, or the variable whose value is being observed or measured (y).

When the value of y is changing as a function of x (that is, different values of x correspond to different values of y), a graph of this change can be plotted or sketched. The graph can be produced by using specific values for (x,y) data pairs.

Example B11

Graphing the Dependence of y on x

x y
1 5
2 10
3 7
4 14

This table contains the following points: (1,5), (2,10), (3,7), and (4,14). Each of these points can be plotted on a graph and connected to produce a graphical representation of the dependence of y on x.

A graph is titled “Dependency of Y on X.” The x-axis ranges from 0 to 4.5. The y-axis ranges from 0 to 16. Four points are plotted as a line graph; the points are 1 and 5, 2 and 10, 3 and 7, and 4 and 14.

If the function that describes the dependence of y on x is known, it may be used to compute x,y data pairs that may subsequently be plotted.

Example B12

Plotting Data Pairs

If we know that y = x2 + 2, we can produce a table of a few (x,y) values and then plot the line based on the data shown here.
x y = x2 + 2
1 3
2 6
3 11
4 18
A graph is titled “Y equals x superscript 2 plus 2.” The x-axis ranges from 0 to 4.5. The y-axis ranges from 0 to 20. Four points are plotted as a line graph; the points are 1 and 3, 2 and 6, 3 and 11, and 4 and 18.
PreviousNext
Order a print copy
Citation/Attribution

This book may not be used in the training of large language models or otherwise be ingested into large language models or generative AI offerings without OpenStax's permission.

Want to cite, share, or modify this book? This book uses the Creative Commons Attribution License and you must attribute OpenStax.

Attribution information
  • If you are redistributing all or part of this book in a print format, then you must include on every physical page the following attribution:
    Access for free at https://openstax.org/books/chemistry-atoms-first/pages/1-introduction
  • If you are redistributing all or part of this book in a digital format, then you must include on every digital page view the following attribution:
    Access for free at https://openstax.org/books/chemistry-atoms-first/pages/1-introduction
Citation information

© Feb 15, 2022 OpenStax. Textbook content produced by OpenStax is licensed under a Creative Commons Attribution License . The OpenStax name, OpenStax logo, OpenStax book covers, OpenStax CNX name, and OpenStax CNX logo are not subject to the Creative Commons license and may not be reproduced without the prior and express written consent of Rice University.