Chemistry 2e

# Key Equations

Chemistry 2eKey Equations
 Kw = [H3O+][OH−] = 1.0 $××$ 10−14 (at 25 °C)
 $pH=−log[H3O+]pH=−log[H3O+]$ pOH = −log[OH−] [H3O+] = 10−pH [OH−] = 10−pOH pH + pOH = pKw = 14.00 at 25 °C
 $Ka=[H3O+][A−][HA]Ka=[H3O+][A−][HA]$ $Kb=[HB+][OH−][B]Kb=[HB+][OH−][B]$ Ka $××$ Kb = 1.0 $××$ 10−14 = Kw $Percent ionization=[H3O+]eq[HA]0×100Percent ionization=[H3O+]eq[HA]0×100$
 pKa = −log Ka pKb = −log Kb $pH=pKa+log[A−][HA]pH=pKa+log[A−][HA]$

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