Skip to ContentGo to accessibility page
Algebra 1

8.8.2 Recognizing the Expanded Product of the Difference of Two Squares

Algebra 18.8.2 Recognizing the Expanded Product of the Difference of Two Squares

8.8.2 Recognizing the Expanded Product of the Difference of Two Squares

8.8.2 • Recognizing the Expanded Product of the Difference of Two Squares

Activity

1. Clare claims that ( 10 + 3 ) ( 10 − 3 ) ( 10 + 3 ) ( 10 − 3 ) is equivalent to 10 2 − 3 2 10 2 − 3 2 and ( 20 + 1 ) ( 20 − 1 ) ( 20 + 1 ) ( 20 − 1 ) is equivalent to 20 2 − 1 2 20 2 − 1 2 . Do you agree? Show your reasoning.

2. You can use your observations from the first question to mentally solve an expression such as 105 · 95 105 · 95 .

a. First, think about the problem differently. Evaluate ( 100 + 5 ) ( 100 − 5 ) ( 100 + 5 ) ( 100 − 5 ) using the distributive property, or FOIL. Show your reasoning.

b. Check your answer by computing 105 · 95 105 · 95 .

3. Is ( x + 4 ) ( x − 4 ) ( x + 4 ) ( x − 4 ) equivalent to x 2 − 4 2 x 2 − 4 2 ?

a. First, support your thinking using a diagram.

x x 4
x x    
-4    

b. Now, support your thinking using the distributive property, or FOIL.

4. Is ( x + 4 ) 2 ( x + 4 ) 2 equivalent to x 2 + 4 2 x 2 + 4 2 ? Support your answer, either with or without a diagram.

Are you ready for more?

Extending Your Thinking
1.

Explain how your work in the previous questions can help you mentally evaluate 22 · 18 22 · 18 .

2.

Explain how your work in the previous questions can help you mentally evaluate 45 · 35 45 · 35 .

3.

Here is a shortcut that can be used to mentally square any two-digit number. Let's take 83 2 83 2 , for example.

  • 83 is 80 + 3 80 + 3 .

  • Compute 80 2 80 2 and 3 2 3 2 , which gives 6400 and 9. Add these values to get 6409.

  • Compute 80 · 3 80 · 3 , which is 240. Double it to get 480.

  • Add 6409 and 480 to get 6889.

Try using this method to find the squares of some other two-digit numbers. (With some practice, it is possible to get really fast at this!)

Explain why this method works.

Self Check

Which of the following is equivalent to 9 2 − 6 2 ?
  1. ( 9 + 6 ) ( 9 − 6 )
  2. ( 9 + 6 ) ( 9 + 6 )
  3. ( 9 − 6 ) ( 9 − 6 )
  4. ( 9 − 6 ) 2

Additional Resources

Recognizing the Expanded Product of the Difference of Two Squares

Mathematically, something special happens when two binomials that are conjugates are multiplied. In other words, the product of an expression of the form ( a − b ) ( a + b ) a − b ) ( a + b ) results in a unique expression called a difference of two squares. Here are some examples of these special products.

Example 1

Let's look at the expression ( 12 + 5 ) ( 12 − 5 ) ( 12 + 5 ) ( 12 − 5 ) . We want to determine if it is equivalent to 12 2 − 5 2 12 2 − 5 2 .

We can use the distributive property of multiplication over addition, or FOIL process, to multiply.

( 12 + 5 ) ( 12 − 5 ) ( 12 + 5 ) ( 12 − 5 )

= 12 2 − 12 ( 5 ) + 5 ( 12 ) − 5 2 = 12 2 − 60 + 60 − 5 2 = 12 2 − 5 2 = 12 2 − 12 ( 5 ) + 5 ( 12 ) − 5 2 = 12 2 − 60 + 60 − 5 2 = 12 2 − 5 2

So, ( 12 + 5 ) ( 12 − 5 ) ( 12 + 5 ) ( 12 − 5 ) is equivalent to 12 2 − 5 2 12 2 − 5 2 .

Example 2

Let's look at a different example using a variable.

( x + 7 ) ( x − 7 ) ( x + 7 ) ( x − 7 )

Is this equivalent to x 2 − 7 2 x 2 − 7 2 ?

( x + 7 ) ( x − 7 ) ( x + 7 ) ( x − 7 )

= x 2 − 7 x + 7 x − 7 2 = x 2 − 7 2 = x 2 − 49 = x 2 − 7 x + 7 x − 7 2 = x 2 − 7 2 = x 2 − 49

This can also be shown using a diagram.

x x –7
x x x 2 x 2 − 7 x − 7 x
7 7 x 7 x − 7 ( 7 ) − 7 ( 7 )

You have studied this process earlier when you learned the difference of squares.

In this lesson, we will reverse this process to rewrite the standard form of a quadratic expression into its factored form.

It is important to remember the linear term, or middle term of a quadratic trinomial, equals zero only holds true for the difference of squares. It does not work for an expression such as x 2 + 25 x 2 + 25 . (In fact, there is no way to multiply two binomials that would result in this expression.)

Example 3

Is ( x + 5 ) 2 ( x + 5 ) 2 equivalent to x 2 + 25 x 2 + 25 ?

Let's find the equivalent expression for ( x + 5 ) 2 ( x + 5 ) 2 or ( x + 5 ) ( x + 5 ) ( x + 5 ) ( x + 5 ) .

( x + 5 ) 2 = ( x + 5 ) ( x + 5 ) = x 2 + 5 x + 5 x + 25 = x 2 + 10 x + 25 ( x + 5 ) 2 = ( x + 5 ) ( x + 5 ) = x 2 + 5 x + 5 x + 25 = x 2 + 10 x + 25

Since x 2 + 10 x + 25 x 2 + 10 x + 25 is not equivalent to x 2 + 25 x 2 + 25 , these expressions are not the same.

Try it

Recognizing the Expanded Product of the Difference of Two Squares

1. Is the expression ( 8 − 7 ) ( 8 + 7 ) ( 8 − 7 ) ( 8 + 7 ) equivalent to the expression 8 2 − 7 2 8 2 − 7 2 ? Show your reasoning using the distributive property, or FOIL.

2. Is ( x + 4 ) ( x + 4 ) ( x + 4 ) ( x + 4 ) equivalent to x 2 + 4 2 x 2 + 4 2 ? Support your answer with a diagram.

Citation/Attribution
Reuse and redistribution of this content in digital or print format:
  • This book may not be used in the training of large language models or otherwise be ingested into large language models or generative AI offerings without OpenStax's prior written permission.
  • This book uses the Creative Commons Attribution-NonCommercial-ShareAlike License, which means that you can reuse and modify the material only for noncommercial purposes, must attribute OpenStax, and must distribute any derivative works under the same license.
  • Any commercial printing of this textbook, including using a local or custom printer, must be approved by OpenStax, and proper citation provided.
  • OpenStax-copyrighted images, activities, assessments, and similar components of this book are subject to the same licensing – CC-BY-NC-SA. They can be used for noncommercial purposes with attribution. Commercial use requires permission.
  • Permission requests: Anyone who intends to incorporate this content (including text, images, and other components) into large language models, use it in AI offerings, use it commercially (including in print), and/or has questions about another use case is welcome to complete our reuse request form.
Attribution information
  • If you are redistributing all or part of this book in a noncommercial print format, then you must include on every physical page the following attribution:

    Access for free at https://openstax.org/books/algebra-1/pages/about-this-course

  • If you are redistributing all or part of this book in a noncommercial digital format, then for every page that includes OpenStax content, you must license the derivative work under the same CC-BY-NC-SA license as the original, and include on every digital page view the following attribution:

    Access for free at https://openstax.org/books/algebra-1/pages/about-this-course

Citation information

The information below includes the information needed to generate citations in most major styles (APA, MLA, etc.); you must reformat and organize the information as needed to fit the requirements of the style. Use the information below to generate a citation. We recommend using a citation tool such as this one.

© Apr 23, 2026 OpenStax. Textbook content produced by OpenStax is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike License. The OpenStax name, OpenStax logo, OpenStax book covers, OpenStax CNX name, and OpenStax CNX logo, and Rice University name, and Rice University logo trademarks, or wordmarks are not subject to the Creative Commons license and may not be reproduced without the prior and express written consent of Rice University.