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Algebra 1

1.8.3 Writing Equations and Isolating Variables

Algebra 11.8.3 Writing Equations and Isolating Variables

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Activity

Use the following scenario for questions 1 – 7:

Tank A initially contained 124 liters of water. It is then filled with more water, at a constant rate of 9 liters per minute.

1.

How many liters of water are in Tank A after 4 minutes?

2.

How many liters of water are in Tank A after 80 seconds?

3.

How many liters of water are in Tank A after 4 minutes?

4.

How many minutes, mm, have passed when Tank A contains 151 liters of water?

5.

How many minutes, mm, have passed when Tank A contains 191.5 liters of water?

6.

How many minutes, mm, have passed when Tank A contains 270.25 liters of water?

7.

How many minutes, mm, have passed when Tank A contains pp liters of water?

For questions 8 – 14, use the following scenario:

Tank B, which initially contained 80 liters of water, is being drained at a rate of 2.5 liters per minute.

8.

How many liters of water are in Tank B after 30 seconds?

9.

How many liters of water are in Tank B after 7 minutes?

10.

How many liters of water are in Tank B after tt minutes?

11.

For how many minutes, tt, has the water been draining when Tank B contains 75 liters of water?

12.

For how many minutes, tt, has the water been draining when Tank B contains 32.5 liters of water?

13.

For how many minutes, tt, has the water been draining when Tank B contains 18 liters of water?

14.

For how many minutes, tt, has the water been draining when Tank B contains v liters of water?

Video: Isolating the Variable

Watch the following video to further explore the above situation.

Self Check

A pool is filled with 15,000 gallons of water. It loses 200 gallons per day. How many days, d , have passed when the pool has  g gallons of water?
  1. g 200 d
  2. g 200 d
  3. 15 , 000 200 d
  4. 15 , 000 g 200

Additional Resources

Choosing Which Equation to Use

A relationship between quantities can be described in more than one way. Some ways are more helpful than others, depending on what we want to find out. Let’s look at the angles of an isosceles triangle, for example.

Triangle with angles labeled a, b, and a.

The two angles near the horizontal side have equal measurement in degrees, aa.

The sum of angles in a triangle is 180180 , so the relationship between the angles can be expressed as:

a+a+b=180a+a+b=180

Example 1

Suppose we want to find aa when bb is 2020.

a+a+b=180a+a+b=180

2a+20=1802a+20=180

2a=180202a=18020

2a=1602a=160

a=80a=80

Example 2

What is the value of bb if aa is 72.572.5?

a+a+b=180a+a+b=180

72.5+72.5+b=8072.5+72.5+b=80

145+b=180145+b=180

b=35b=35

Notice that when bb is given, we did the same calculation repeatedly to find aa: We substituted bb into the first equation, subtracted bb from 180, and then divided the result by 2.

Instead of taking these steps over and over whenever we know bb and want to find aa, we can rearrange the equation to isolate aa:

a+a+b=180a+a+b=180

2a+b=1802a+b=180

2a=180b2a=180b

a=180b2a=180b2

a=9012ba=9012b

This equation is equivalent to the first one. To find aa, we can now simply substitute any value of bb into this equation and evaluate the expression on the right side.

Likewise, we can write an equivalent equation to make it easier to find bb when we know aa:

a+a+b=180a+a+b=180

2a+b=1802a+b=180

b=1802ab=1802a

Rearranging an equation to isolate one variable is called solving for a variable. In this example, we have solved for aa and for bb. All three equations are equivalent. Depending on what information we have and what we are interested in, we can choose a particular equation to use.

Rewrite the equation a+a+b=180a+a+b=180 as an equivalent equation that could be used to easily find bb.

Try it

Try It: Choosing Which Equation to Use

Jake and Bryce are saving their allowance. Jake saved for one week, and Bryce saved for 2 weeks. Together they saved $15. Write an equation to find Bryce’s allowance.

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